從php變量設置html文本框的值

Question

我試圖根據會話數據在html註冊表單中爲文本框填充默認的「值」字段。

如果用戶在我的註冊表單上發生任何錯誤，它會將其發回，我希望儘可能多地填寫其數據，而不是將它們發送回普通表單以重新開始。

這裏是我的handleer腳本檢查：

// Let's get the text from the form,. 

$username = mysql_real_escape_string($_POST['username']); 
$password = mysql_real_escape_string($_POST['password']); 
$password_check = mysql_real_escape_string($_POST['pwcheck']); 
$email = mysql_real_escape_string($_POST['email']); 
$spam_check = mysql_real_escape_string($_POST['checkit']); // spam check 
$IP = $_SERVER['REMOTE_ADDR']; // log their ip 

// set up some session data for mnistakes or spam or errors 
$_SESSION['username'] = $username; 
$_SESSION['email'] = $email; 

// check for empty info 

if ($username == NULL || $username == '') { // no username set 
    header ("Location: register.php?p=un"); die; 
} 
if ($password == NULL || $password == '') { // no password set 
    header ("Location: register.php?p=pw"); die; 
} 
if ($password_check == NULL || $password_check == '') { // no password check set 
    header ("Location: register.php?p=pwchk"); die; 
} 
if ($email == NULL || $email == '') { // no email set 
    header ("Location: register.php?p=em"); die; 
} 

// have we had Spam? 

if (strlen($spam_check) > 0) { // spam bot alert 
    header ("Location: http://www.google.co.uk"); 
    die ('You\'re naughty.'); 
} 

// does password and check match? 

if ($password != $password_check) { // no match 
    $_SESSION['username'] = $username; 
    $_SESSION['email'] = $email; 
    header ("Location: register.php?p=pwnpc&email=".$email.""); die; 
} 

我的窗體頁上我做：

// check for empty fields and session data 

if (isset($_SESSION['email'])) { // email session data set 
$email_value = 'value = "'.$_SESSION['email'].'"'; 
} else { $email_value = 'placeholder="Email"'; } 

$errors = mysql_real_escape_string($_GET['p']); 

switch ($errors) { // something is empty 
case "un": // no username set 
    $pen_name = 'Pen Name missing!'; 
break; 
case "pw": // no username set 
    $password = 'Password missing!'; 
break; 
case "pwchk": // no password check set 
    $pw_check = 'Your passwords don\'t match!'; 
break; 
case "em": // no username set 
    $email = 'Email missing!'; 
break; 
case "pwnpc": // passwords don't match 
    $pw_mismatch = 'Passwords don\'t match!'; 
break; 
} 

和形式自身

<form action="register_handle.php" method="post"> 

<label>Choose a Pen Name</label><br /><?php echo $pen_name ?> 
<p><input type="text" name="username" placeholder="Pen Name" autofocus required> </p> 

<label>Choose a Password</label><br /> 
<p><input type="password" name="password" placeholder="Password" required> ---> <input type="password" name="pwcheck" placeholder="Password Confirm" required> <?php echo $password.$pw_check.$pw_mismatch ?></p> 

<label>Email</label><br /> 

<?php echo $email ?> 

<p><input type="email" name="email" <?php echo $email_value ?> required></p> 

<input id="checkit" type="text" name="checkit" maxlength="50" size="30"> 

<input type="submit" value=" Sign Me Up " name="submit" class="submit"> 

</form> 

，但我不能似乎沒有回到價值。我相信這一定很簡單，但你能在這裏看到問題嗎？正如你所看到的，我迄今爲止只在電子郵箱中嘗試過，但無濟於事。

Answer 1

你缺少value attribute在<input>領域：

<p><input type="email" name="email" value="<?php echo htmlentities($email_value) ?>" placeholder="Email" required></p> 

這將打破你想使用的佔位符，但應該總是存在的，因爲無論如何，如果你提供一個值它不會顯示。