MySQL查詢：選擇GROUP_ID但如果所述組中的任何的client_id是= X然後不選擇

Question

Sqlfiddle是http://sqlfiddle.com/#!2/7df50/4

基本上，我有3個表：組，成員，客戶端。

tbl.client = client_id (PK, AI), industry_id (FK), status 
tbl.membership = membership_id (PK, AI), Client_id (FK to tbl.client), 
    group_id (FK to group), status 
tbl.group = group_id (PK, AI), target_market_id (FK), geography_id (FK) 

基本上，我想通過參加全部3個表來選擇GROUP_ID，其中客戶端都不能有等於給定的輸入（$ client_industry_id）一client.industry_id。

我的查詢到目前爲止是：

"select g.group_id from `group` g join membership m on m.group_id=g.group_id ". 
"join client c on c.client_id=m.client_id ". 
"where g.status=1 and m.status=1 and c.status=1 and ". 
"g.geography_id=$target_geography and ". 
"g.target_market_id=$target_market ". 
"c.industry_id <> $client_industry_id"; 

與查詢的問題是，它仍然會選擇組GROUP_ID因爲爲了跳閘<所有客戶必須沒有CLIENT_ID = $ client_industry_id> 。我希望這是有道理的？

我會通過分組來解決這個問題嗎？如果陳述？

編輯：

insert into client (email, industry_id, status) VALUES ('email1@gmail.com', '1', '1') 
insert into client (email, industry_id, status) VALUES ('email2@gmail.com', '2', '1') 
insert into client (email, industry_id, status) VALUES ('email3@gmail.com', '2', '1') 

insert into membership (client_id, group_id) VALUES (1, 1) 
insert into membership (client_id, group_id) VALUES (2, 1) 
insert into membership (client_id, group_id) VALUES (3, 2) 

insert into group (geography_id, target_market_id) VALUES (1, 1) 
insert into group (geography_id, target_market_id) VALUES (1, 1) 

#psuedo code 
"select group_id from group join membership on group_id, join client on client_id where 
    all status=1 and group.geography_id=1 and group.target_market_id=1 and 
    NONE of the clients have client.industry_id=1 

-- query should result in group_id=2 

Answer 1

你和@Strawberry是正確的，前面的代碼不可能奏效。對於那個很抱歉。而且這裏有一個快速裂紋你可能會想嘗試，而不是什麼：

select g.group_id from groupp g 
join membership m on m.group_id=g.group_id and m.status=1 //to consider check on status 
join client c on c.client_id=m.client_id and c.status=1 //to consider check on status 
where g.group_id not in (select mm.group_id from membership mm join client cc on mm.client_id=cc.client_id and cc.industry_id = $client_industry_id) and //to exclude groups with clients that have industry 
g.status=1 and 
g.geography_id=$target_geography and 
g.target_market_id=$target_market;