MySQL查詢選擇

Question

1臺

GroupID MemberID Name 
    1  1  ---  
    1  23  ---  
    2  1  ---  
    2  23  ---  
    2  24  ---  
    3  1  ---  
    3  24  ---  

第二臺

ID MemberCount GroupName 
1  2   --- 
2  3   --- 
3  2   --- 

現在我想

select the GroupID where MemberID = (1 and 23) and MemberCount = 2 

我使用MySQL和交叉而我該怎麼不能用這樣做

Answer 1

SELECT a.groupID 
FROM table1 a 
, table2 b 
WHERE b.id = a.groupID 
AND b.MemberCount = 2 
AND a.MemberId in (1,23) 
HAVING COUNT(DISTINCT(MemberId)) >= 2; 

Answer 2

這應該工作...我猜的名字。在（1,23）`

SELECT g.id 
FROM group g 
WHERE g.membercount = 2 
AND EXISTS (SELECT null FROM user_group ug WHERE ug.groupid = g.id AND ug.memberid = 1) 
AND EXISTS (SELECT null FROM user_group ug WHERE ug.groupid = g.id AND ug.memberid = 23) 

Answer 3

select GroupID from table1 inner join table2 on table1.GroupID=table2.ID where MemberCount=2 and MemberID in (1,23);