如何使用參數傳遞塊的方法

Question

如何無效的typedef傳遞給方法

我有一個typedef

typedef void (^FBLoginHandler)(id <FaceBook>,bool,NSError *error); 

FBLoginHandler testHandler;

^(id<FBLoginHandler>, bool, NSError *)error 

[login log:@"AccessToken" handler:^(id<FBLoginHandler>, bool, NSError *)error]; 

任何一個可以建議我如何的typedef值傳遞給方法

[login log:@"AccessToken" handler:???]; 

Answer 1

[login log:@"AccessToken" handler:^(id<FaceBook> object, bool trueOrFalse, NSError *error){ 
    // ... do whatever you'd like to do here. 
}]; 

或...

void ^(handlerBlock)(id<FaceBook>, bool, NSError *) = ^(id<FaceBook> object, bool trueOrFalse, NSError *error) { 
    // ... do whatever you'd like to do here 
}; 

[login log:@"AccessToken" handler:handlerBlock]; 

或...

[login log:@"AccessToken" handler:nil];