用引號解析json數據

我製作了一個解析來自URL的數據的android應用程序。只要json數據returnedL中沒有引號，應用程序就可以正常工作。有沒有一種方法來解析與Java JSON數據，當數據有這樣的標誌：用引號解析json數據

{ 
"cate": 
[ 
    { 
    "title": "this is the "title" like ", 
    "EdId": "445", 
    "date": "Sep 25, 2014" 
    } 
] 
}

這裏是代碼我一起工作：

public class Guys extends Activity { 
    ListView list; 
    TextView title; 
    TextView EdId; 
    TextView date; 
    Button Btngetdata; 
    //Button nextac; 
    ArrayList<HashMap<String, String>> oslist = new ArrayList<HashMap<String, String>>(); 

    //URL to get JSON Array 
    private static String url = "http://10.10.10.2/test/ff.php"; 



    //JSON Node Names 
    //private static final String ca 
    private static final String TAG_CAT = "cate"; 
    private static final String TAG_TITLE = "title"; 
    private static final String TAG_EDID = "EdId"; 
    private static final String TAG_DATE = "date"; 

    JSONArray cate = null; 




    @Override 
    protected void onCreate(Bundle savedInstanceState) { 
     super.onCreate(savedInstanceState); 

     setContentView(R.layout.test_main); 
     oslist = new ArrayList<HashMap<String, String>>(); 

     new JSONParse().execute(); 



    } 



    private class JSONParse extends AsyncTask<String, String, JSONObject> { 
     private ProgressDialog pDialog; 
     @Override 
     protected void onPreExecute() { 
      super.onPreExecute(); 
      title = (TextView)findViewById(R.id.title); 
      EdId = (TextView)findViewById(R.id.edid); 
      date = (TextView)findViewById(R.id.date); 
      pDialog = new ProgressDialog(Guys.this); 
      pDialog.setMessage("Getting Data ..."); 
      pDialog.setIndeterminate(false); 
      pDialog.setCancelable(true); 
      pDialog.show(); 



     } 

     @Override 
     protected JSONObject doInBackground(String... args) { 
      String jn="ff'f'd"; 
      JSONParser jParser = new JSONParser(); 

      // Getting JSON from URL 
      JSONObject json = jParser.getJSONFromUrl(url); 
        json.toString();  


      return json; 
     } 
     @Override 
     protected void onPostExecute(JSONObject json) { 
      pDialog.dismiss(); 
      try { 



       //json = json.substring(7); 

        // Getting JSON Array from URL 
        cate = json.getJSONArray(TAG_CAT); 
        for(int i = 0; i < cate.length(); i++){ 
        JSONObject c = cate.getJSONObject(i); 

        // Storing JSON item in a Variable 
        String title = c.getString(TAG_TITLE); 
        String EdId = c.getString(TAG_EDID); 
        //String date = c.getString(TAG_API); 




        // Adding value HashMap key => value 


        HashMap<String, String> map = new HashMap<String, String>(); 

        map.put(TAG_TITLE, title); 
        map.put(TAG_EDID, EdId); 
        //map.put(TAG_API, date); 

        oslist.add(map); 
        list=(ListView)findViewById(R.id.list); 





        ListAdapter adapter = new SimpleAdapter(Guys.this, oslist, 
          R.layout.list_v, 
          new String[] { TAG_TITLE}, new int[] { 
            R.id.title}); 

        list.setAdapter(adapter); 
        list.setOnItemClickListener(new AdapterView.OnItemClickListener() { 

         @Override 
         public void onItemClick(AdapterView<?> parent, View view, 
               int position, long id) { 
          Toast.makeText(Guys.this, "You Clicked at "+oslist.get(+position).get("EdId"), Toast.LENGTH_SHORT).show(); 
          Intent myIntent = new Intent(Guys.this, SimpleBrowser.class); 


          String idurl = oslist.get(+position).get("EdId"); 
          String idsend = idurl; 

          myIntent.putExtra("id",idurl.toString()); 
          Guys.this.startActivity(myIntent); 
         } 
        }); 

        } 
      } catch (JSONException e) { 
       e.printStackTrace(); 




      } 


     } 
    } 





}

來源

2014-10-12 kaso naim

您的JSON是無效的！ – mmlooloo 2014-10-12 13:33:16

我很想知道爲什麼這個問題的編輯被批准了，特別是因爲它引入了新的拼寫錯誤，並且通過刪除「引號」中的「引用」一詞來掩蓋了問題。 – 2014-10-12 15:39:07

我不能從json對象中刪除引號，因爲這個json對象是聯機的，我嘗試創建一個android應用程序來解析來自這個網站的新聞所以如果有一些消息有引用我的json沒有解析數據 – 2014-10-12 15:46:41

我認爲這個問題是與系統生產json字符串，在生產者系統中，您需要轉義"字符替換爲\"或使用' charachter替代。

來源

2014-10-12 13:09:07 dursun

您可以使用gson類來解析json響應。您需要創建一個類

class Data{ 

    ArrayList<Data> cate; 
    getCateList(){ 
     return cate; 
    } 
    String title; 
    String EdId; 
    String date; 
} 


InputStream source = retrieveStream(url); 
Gson gson = new Gson(); 
Reader reader = new InputStreamReader(source); 
Data response = gson.fromJson(reader, Data.class);

閱讀下面的教程：http://www.javacodegeeks.com/2011/01/android-json-parsing-gson-tutorial.html

來源

2014-11-04 07:33:44

用引號解析json數據

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