如何在PHP中以水平網格顯示數據庫數據

如何顯示水平網格中的數據庫數據。我有垂直顯示的代碼。但我需要它以horzontally顯示。如何在PHP中以水平網格顯示數據庫數據

<?php 

$connect=mysql_connect("localhost","root","user"); 
mysql_selectdb("form"); 
$result=mysql_query("SELECT * FROM cath"); 
//echo "The details are...."; 

$dyn_table = '<table border="2" cellpadding="10">'; 

while($cath=mysql_fetch_array($result)) 
{ 

    $ID=$cath["ID"]; 
    $name=$cath["name"]; 
    $email=$cath["email"]; 
    $number=$cath["number"]; 
    $org=$cath["org"]; 
    $message=$cath["message"]; 

     if ($cath==$cath) 
     { 
     $dyn_table .= '<tr><td>' . $name . '</td>'; 
     $dyn_table .= '<tr><td>' . $email . '</td>'; 
     $dyn_table .= '<tr><td>' . $number . '</td>'; 
     $dyn_table .= '<tr><td>' . $org . '</td>'; 
     $dyn_table .= '<tr><td>' . $message . '</td>'; 
     } 

} 

$dyn_table .= '</tr></table>'; 
?> 

<html> 
<body> 
<h3>PHP GRID LAYOUT</h3> 
<?php 
echo $dyn_table; 
?> 
</body> 
</html>

你能幫我解決這個問題嗎？等待最佳解決方案。

感謝

Cathi

來源

2013-04-30 Cathi Jesus

你能移動錶行創建到你的if語句的頂部和底部？

while($cath=mysql_fetch_array($result)) 
{ 
    $ID=$cath["ID"]; 
    $name=$cath["name"]; 
    $email=$cath["email"]; 
    $number=$cath["number"]; 
    $org=$cath["org"]; 
    $message=$cath["message"]; 

    if ($cath==$cath) 
    { 
     $dyn_table .= '<tr>'; 
     $dyn_table .= '<td>' . $name . '</td>'; 
     $dyn_table .= '<td>' . $email . '</td>'; 
     $dyn_table .= '<td>' . $number . '</td>'; 
     $dyn_table .= '<td>' . $org . '</td>'; 
     $dyn_table .= '<td>' . $message . '</td>'; 
     $dyn_table .= '</tr>'; 
    } 
} 

$dyn_table .= '</table>';

來源

2013-04-30 07:46:50

如何在PHP中以水平網格顯示數據庫數據

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