0
我對SQL和所有自學的新手都很在意，所以在技術太過時請記住這一點！基於Common Column SQL Server的行合併
我有一個教堂數據庫工作。我們有一張桌子，可以將家庭ID分配給一組家庭中的人。我有一個包含所有家庭ID的表格，並且有一列包含與該家庭ID關聯的唯一人員ID。當我對查詢特定家庭ID的表進行查詢時，我得到與該家庭ID關聯的每個唯一人員ID的一行。
我需要做的是結合家庭陷入了一排一列和孩子們的另一個名字顯示成年人的名字。然後是列中的姓氏和列中的地址。
當我使用這個我可以成功做到這一點：
DECLARE @FirstNames VARCHAR (MAX)
DECLARE @Children VARCHAR (MAX)
DECLARE @Address VARCHAR (MAX)
DECLARE @LastName VARCHAR (MAX)
SELECT @FirstNames = COALESCE(@FirstNames+', ','') + pb.first_name,
@Address = pb.Address,
@LastName = pb.last_name
FROM core_v_person_basic pb
JOIN core_family_member fm ON fm.person_id = pb.person_id
WHERE fm.role_luid = 29
AND fm.family_id = 13783
SELECT @Children = COALESCE(@Children+', ','') + pb.first_name
FROM core_v_person_basic pb
JOIN core_family_member fm ON fm.person_id = pb.person_id
WHERE fm.role_luid = 31
AND fm.family_id = 13783
SELECT
@FirstNames AS 'First Names',
@LastName AS 'Last Name',
@Children AS 'Children',
@Address AS 'Address'
但問題是一個家族ID這僅適用。我希望能夠顯示以此方式格式化的所有家庭ID，或者顯示一組特定的家庭ID。例如，我可能想要顯示來自不同表格的某個班級中的所有家庭。
我需要一個解決方案，具有足夠的靈活性讓我身邊將其更改爲不同的列添加到根據需要的結果。
非常感謝您的幫助！
UPDATE 下面是我從貝爾巴托夫Kyuchukov的回答修改查詢： - 模擬你的表進行樣品的緣故（您將要替換這些變量與表名中的代碼，直到樣本結束）：
DECLARE @core_family_member AS TABLE
(family_id int,
person_id int,
date_created datetime,
date_modified datetime,
created_by varchar(50),
modified_by varchar(50),
role_luid int,
organization_id int)
DECLARE @core_v_person_basic AS TABLE (
person_id int,
guid uniqueidentifier,
suffix varchar(50),
nick_name nvarchar(50),
first_name nvarchar(50),
last_name nvarchar(50),
birth_date datetime,
address_id int,
Address varchar(201),
street_address_1 varchar(100),
street_address_2 varchar(100),
city varchar(64),
state varchar(12),
postal_code varchar(24),
member_status_luid int,
member_status varchar(50),
record_status varchar(8),
gender varchar(1),
marital_status_luid int,
marital_status varchar(50),
home_phone varchar(50),
list_home_phone varchar(50),
business_phone varchar(50),
list_business_phone varchar(50),
cell_phone varchar(50),
list_cell_phone varchar(50),
email varchar(80),
area_id int,
area_name varchar(100),
organization_id int,
photo_guid varchar(80),
envelope_number int,
restricted bit)
INSERT INTO
@core_v_person_basic
SELECT * FROM core_v_person_basic
INSERT INTO
@core_family_member
SELECT * FROM core_family_member
-- Here children and parents are selected separately with a family ID to join by (these are called CTE-s for Common Table Expression - they will make the final statement more clear):
;WITH
Children AS (
SELECT
fm.family_id,
pb.first_name AS child_first_name
FROM
@core_v_person_basic pb
INNER JOIN @core_family_member fm
ON fm.person_id = pb.person_id
WHERE
fm.role_luid = 31
),
Parents AS (
SELECT
fm.family_id,
pb.first_name AS parent_first_name
FROM
@core_v_person_basic pb
INNER JOIN @core_family_member fm
ON fm.person_id = pb.person_id
WHERE
fm.role_luid = 29
),
Address AS (
SELECT
pb.address AS 'Address'
FROM
@core_v_person_basic pb)
-- Here stuff() function is used to concatenate the members grouped by family ID - basically an XML is "stuffed" similar to your variables and then the ready value is taken using the value() function:
SELECT
stuff((
SELECT
', ' + p.parent_first_name
FROM
Parents p
WHERE
f.family_id = p.family_id
FOR XML PATH(''), TYPE
).value('(./text())[1]', 'VARCHAR(MAX)')
, 1, 1, '') AS parents_names,
stuff((
SELECT
', ' + c.child_first_name
FROM
Children c
WHERE
f.family_id = c.family_id
FOR XML PATH(''), TYPE
).value('(./text())[1]', 'VARCHAR(MAX)')
, 1, 1, '') AS children_names
FROM
Parents f
GROUP BY
f.family_id
這更接近我所需要的，但我仍然不能添加比已有的更多的列。這似乎是因爲Group By語法。如何提出額外的列任何幫助將是真棒！
解決方案！ 我得到它的工作就像我需要！以下是更多專欄和信息的工作查詢！
WITH
Children AS (
SELECT
fm.family_id,
pb.first_name AS child_first_name
FROM
core_v_person_basic pb
INNER JOIN core_family_member fm
ON fm.person_id = pb.person_id
WHERE
fm.role_luid = 31
),
Parents AS (
SELECT
fm.family_id,
pb.Address,
pb.city,
pb.state,
pb.postal_code,
pb.record_status,
pb.last_name,
pb.first_name AS parent_first_name
FROM
core_v_person_basic pb
INNER JOIN core_family_member fm
ON fm.person_id = pb.person_id
WHERE
fm.role_luid = 29
),
RecordStatus AS (
SELECT
fm.family_id,
pb.record_status AS record_status
FROM
core_v_person_basic pb
JOIN core_family_member fm On fm.person_id = pb.person_id
),
InactiveReason AS (
SELECT
fm.family_id,
ir.inactive_reason_value AS inactive_reason
FROM
core_person cp
JOIN core_family_member fm ON cp.person_id = fm.person_id
JOIN core_v_inactive_reason ir ON ir.inactive_reason_id = cp.inactive_reason_luid
)
-- Here stuff() function is used to concatenate the members grouped by family ID - basically an XML is "stuffed" similar to your variables and then the ready value is taken using the value() function:
SELECT
stuff((
SELECT
', ' + p.parent_first_name
FROM
Parents p
WHERE
f.family_id = p.family_id
FOR XML PATH(''), TYPE
).value('(./text())[1]', 'VARCHAR(MAX)')
, 1, 1, '') AS 'First Name(s)',
f.last_name,
stuff((
SELECT
', ' + c.child_first_name
FROM
Children c
WHERE
f.family_id = c.family_id
FOR XML PATH(''), TYPE
).value('(./text())[1]', 'VARCHAR(MAX)')
, 1, 1, '') AS 'Children',
f.Address,
f.city,
f.state,
f.postal_code,
STUFF((
SELECT
', ' + r.record_status
FROM
RecordStatus r
WHERE
f.family_id = r.family_id
FOR XML PATH(''), TYPE
).value('(./text())[1]', 'VARCHAR(MAX)')
, 1, 1, '') AS 'Record Status',
STUFF((
SELECT
', ' + i.inactive_reason
FROM
InactiveReason i
WHERE
f.family_id = i.family_id
FOR XML PATH(''), TYPE
).value('(./text())[1]', 'VARCHAR(MAX)')
, 1, 1, '') AS 'Record Status'
FROM
Parents f
GROUP BY
f.family_id,
f.Address,
f.city,
f.state,
f.postal_code,
f.last_name
謝謝大家的幫助！
這裏有一個例子，根據家族ID將多行記錄到一行中。如果你爲父母和子女列做到這一點，你應該有你以後http://stackoverflow.com/questions/15477743/listagg-in-sqlserver – xQbert
xQbert，這工作得很好，但如果我需要引入另一個表，則不會。這使我可以查看與家庭ID相關的所有人員ID，但是我需要再拉一張表格，告訴我具有該人員ID的人員的姓名。 –