鏈接的cpp文件 - 不能在其他文件中使用getline

我知道這可能看起來像一個簡單的問題，但我有一個課堂作業，使20問題類型的遊戲。我想我會多做一點菜單。該程序運行良好，但是當我輸入實際的遊戲文件時，它會輸出第一行然後輸出到我的最後一行並輸出它......它不會讓我鍵入和玩遊戲。這很容易解決嗎？鏈接的cpp文件 - 不能在其他文件中使用getline

當我開始我的程序時，菜單運行正常。它提示用戶輸入導航（1 =玩遊戲，2 =指令，3 =字數據庫，4 =退出）。當我按1支付遊戲時，它會像屏幕一樣清除屏幕，但不是讓我回答第一個問題（動物，食物，元素等），它說：「它是動物，食物，元素，或其他？（輸入a，f，e或o進行選擇）「，就像它應該那樣，但是接着我輸入1並將其用作此問題的輸入，使其輸出」這不是一個選項！「在提示輸入關閉程序之前。我怎樣才能解決這個問題？我並不熱衷於包括我所有的代碼，因爲它是幾百線長，但這裏是我的菜單文件，頭文件，和我的遊戲文件的開頭：

myheader.h：

#include <windows.h> 
#include <iostream> 

void runGame(); 
void showHowTo(); 
void showWords(); 
void mainMenu();

menu.cpp：

#include <iostream> 
#include <string> 
#include "myheader.h" 
#include <windows.h> 

using namespace std; 

int main() 
{ 

    int x = 0; 
    cout << "*******************************\n"; 
    cout << "*****20 QUESTIONS**************\n"; 
    cout << "*******************************\n\n"; 

    cout << "Press a key to make a selection.\n\n\n"; 

    cout << "1: Play Game" << endl; 
    cout << "2: View Instructions" << endl; 
    cout << "3: View Word Database" << endl; 
    cout << "4: Close Window\n\n\n"; 

    cin >> x; 

    if (x == 1) 
    { 
     system("cls"); 
     runGame(); 
    } 
    else if (x == 2) 
    { 
     //instructions function would be here, but was removed as it is not relevant to my question 
    } 
    else if (x == 3) 
    { 
     //word database function would be here, but was removed as it is not relevant to my question 
    } 
    else if (x == 4) 
    { 
     system("pause"); 
     return 0; 
    } 



    system("pause"); 
    return 0; 
}

game.cpp：

#include <iostream> 
#include <string> 
#include "myheader.h" 
#include <windows.h> 

using namespace std; 

void runGame() 
{ 
    //declaring variables 

    string userInput = ""; 
    bool no = ((userInput == "no") || (userInput == "No") || (userInput == "NO") || (userInput == "nO")); 
    string disappointment = "Awww... Oh well, maybe I'll get it next time!\n"; 
    string excitement = "Yay! I feel smart!\n"; 
    bool animal = ((userInput == "A") || (userInput == "a")); 
    bool food = (userInput == "F" || userInput == "f"); 
    bool element = (userInput == "E" || userInput == "e"); 
    bool other = (userInput == "O" || userInput == "o"); 

    // Prompt user for input (animal, vitamin, element, or other 

    cout << "Welcome to 20 Questions!\nPlease think of something, and answer the questions honestly!\n\n"; 
    cout << "Is your object an animal, vitamin, element, or other? (Please answer A, F, E, or O)\n"; 
    getline(cin,userInput); 
    animal = ((userInput == "A") || (userInput == "a")); 
    food = (userInput == "F" || userInput == "f"); 
    element = (userInput == "E" || userInput == "e"); 
    other = (userInput == "O" || userInput == "o"); 

    if (animal) 
    { 
     //full game in here 
    } 
    else 
    { 
     cout << "That's not an option!\n"; 
    } 

    system("pause"); 
}

這些都是代碼文件，我掙扎......請不要指出系統（「暫停」）效率不高，我已經知道了。我只需要知道如何在遊戲開始運行時讓我的用戶輸入工作。如果我的描述很糟糕，這些是我輸出的照片。

菜單：