MySQL的JOIN + COUNT + WHERE +和

我區的表：MySQL的JOIN + COUNT + WHERE +和

table region: 
id | title

地區有許多廣告：

table advert: 
id | region_id | ...

然後廣告有很多用途（多對多通過表adv_use）：

table use: 
use | slug | ... 
---------------- 
1 | slug_1 | ... 
2 | slug_2 | ... 
.................. 



table adv_use: 
adv_id | use_id

我想要選擇所有具有count（*）個廣告的區域，這些廣告使用了slug_1和slug_2。如果廣告對slug_1或slug_2（或兩者）沒有用處，則不得計算在內。我現在擁有的一切：

SELECT COUNT(DISTINCT advert.id) as count 
FROM region 
JOIN advert ON region.id = advert.region_id 
JOIN adv_use ON advert.id = adv_use.adv_id 
JOIN use ON adv_use.use_id = use.id 
WHERE use.slug IN ('slug_1', 'slug_2') 
GROUP BY region.id 
HAVING COUNT(DISTINCT adv_use.use_id) = 2

但它的工作不是我想要的。 SQLFiddle：http://sqlfiddle.com/#!2/5b4d4/1

感謝您的幫助和對英語不好的抱歉。

來源

2013-11-28 Phantaminuum

你不能指望'advert.id'如果你也有'advert.id'在'GROUP BY'。 – Barmar

如果我從GROUP BY中刪除它，它仍然是錯誤的。它是忽略HAVING語句並僅通過use.slug IN（'slug_1'，'slug_2'） – Phantaminuum

SQLFiddle：http://sqlfiddle.com/#!2/5b4d4/1 – Phantaminuum

您需要使用子查詢來選擇使用這兩種子彈的adv_id：

SELECT COUNT(DISTINCT advert.id) as count, region.id as reg_id 
FROM region 
JOIN advert ON region.id = advert.region_id 
JOIN (SELECT adv_use.adv_id 
     FROM adv_use 
     JOIN tbl_use ON adv_use.use_id = tbl_use.id 
     WHERE tbl_use.slug IN ('slug1', 'slug2') 
     GROUP BY adv_use.adv_id 
     HAVING COUNT(DISTINCT adv_use.use_id) = 2) adv_use 
ON advert.id = adv_use.adv_id 
GROUP BY region.id 
;

SQLFIDDLE

來源

2013-11-28 11:05:40 Barmar

謝謝，完美的作品！ – Phantaminuum

MySQL的JOIN + COUNT + WHERE +和

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