如何拆分列表中的字符串並使用輸出與字典進行比較？

Question

假設我的字典有

{'one': '1','two': '2', ..., 'hundred': '100'} 

和我的列表中包含

[['for 30']['for thirty']] 

我想在列表中的字符串分割爲：

[for],[30] and [for],[thirty] 

然後我想用'thirty'來與字典中的相應條目進行比較，並獲得'30'作爲輸出。

import csv 

reader = csv.reader(open('dict.csv', 'r')) 
d = {} 
for row in reader: 
    k, v = row 
    d[k] = v 

with open('test_term.csv', 'rb') as f: 
    reader = csv.reader(f) 
    your_list = list(reader) 

Answer 1

歡迎來到Python！你應該真的閱讀一些基本知識，比如如何聲明一個列表和一個字典。

我猜你試圖做的是：

# this is how you format a list 
pair_list = ['for 30', 'for thirty', 'for 1', 'for two'] 
# this is how you format a dict 
resolve_dict = {'one': '1', 'thirty': '30', 'hundred': '100'} 

# iterate the list two strings at a time 
for idx in xrange(len(pair_list)): 
    # example in comments 
    # pairs[idx] == 'for 30' 
    splitted = pair_list[idx].split(' ') 
    # splitted == ['for', '30'] 
    number = splitted[1] 
    # number == '30' 

    # pairs[idx + 1] == 'for thirty' 
    splitted = pair_list[idx + 1].split(' ') 
    # splitted == ['for', 'thirty'] 
    word = splitted[1] 
    # word == 'thirty' 

    # comparison 
    if resolve_dict[word] == number: 
     print 'hurray?'