爲什麼我的python代碼沒有完全運行

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任何人都可以幫助我理解爲什麼我非常簡單的岩石剪刀代碼卡在第18行末尾並退出？我已經測試過每個部分單獨和它的工作，它可能不是最漂亮的代碼，但它似乎做的工作，但在它的最新itteration它只是退出第18行，退出代碼0，所以沒有錯誤，一點兒也不說什麼是錯的，它只是doesn't執行下一行，就像看到一隻破或該線路上的退出，但有isn't：爲什麼我的python代碼沒有完全運行

import random 

def startgame(): 
    print("Please choose rock - r, paper - p or scissors - s:") 
    pchoice = input(str()) 
    if(pchoice.lower in ["r","rock"]): 
     pchoice = "0" 
    elif(pchoice.lower in ["s","scissors"]): 
     pchoice = "1" 
    elif(pchoice.lower in ["p","paper"]): 
     pchoice = "2" 
    cchoice = (str(random.randint(0,2))) 
    if(cchoice == "0"): 
     print("Computer has chosen: Rock \n") 
    elif(cchoice == "1"): 
     print("Computer has chosen: Scissors \n") 
    elif(cchoice == "2"): 
     print("Computer has chosen: Paper \n") 
#runs perfect up to here, then stops without continuing 
    battle = str(pchoice + cchoice) 
    if(battle == "00" and "11" and "22"): 
     print("Draw! \n") 
     playagain() 
    elif(battle == "02" and "10" and "21"): 
     if(battle == "02"): 
      print("You Lose! \nRock is wrapped by paper! \n") 
     elif(battle == "10"): 
      print("You Lose! \nScissors are blunted by rock! \n") 
     elif(battle == "21"): 
      print("You Lose! \nPaper is cut by scissors! \n") 
      playagain() 
    elif(battle == "01" and "12" and "20"): 
     if(battle == "01"): 
      print("You Win! \nRock blunts scissors! \n") 
     elif(battle == "12"): 
      print("You Win! \nScissors cut paper! \n") 
     elif(battle == "20"): 
      print("You Win! \nPaper wraps rock! \n") 
      playagain() 

def main(): 
    print("\nWelcome to Simon´s Rock, Paper, Scissors! \n \n") 
    startgame() 

def playagain(): 
     again = input("Would you like to play again? y/n \n \n") 
     if(again == "y"): 
      startgame() 
     elif(again == "n"): 
      print("Thank you for playing") 
      exit() 
     else: 
      print("Please choose a valid option...") 
     playagain() 

main()

來源

2017-08-14 Rayne

嘗試打印戰鬥值，並將其與連續if語句中的內容進行比較。 –

你有沒有重複這個問題的條目？ – Miket25

提供的代碼有很多問題。有些已經在答案中解釋過，有些則不是。例如，無論你有'.lower'還是'.upper'，都應該是'lower（）'和'upper（）'。否則，這些「if」條件永遠不會是「真」。 – DeepSpace

在像 if(battle == "00" and "11" and "22"): 使用in操作線 if(battle in ["00", "11", "22"]):

playagain()沒有被調用，因爲沒有條件是真的。

來源

2017-08-14 13:52:09

的錯誤是在這：

if(battle == "00" and "11" and "22"):

這將評估在所有情況下False但00，您需要將其更改爲：

if battle == "00" or battle == "11" or battle == "22":

而且也是您使用and

您的發言被解讀爲以下其他兩個語句：由於您使用

True/False 1- if battle == "00" 
True  2- and "11" #<-- here it checks if the string is True which means string is not empty 
True  3- and "22" is True #<-- here too

所以，你的語句將只有當所有陳述True工作and要求聲明的所有部分爲True。第二和第三部分總是True因此它的檢查，如果選擇的是"00"

你需要的是這樣的：

1- if battle == "00" True/False 
2- or battle == "11" True/False 
3- or battle == "22" True/False

而你只需要一個部分是True這裏，因爲運行該語句的or

來源

2017-08-14 13:52:07

爲什麼我的python代碼沒有完全運行

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