爲什麼我的python代碼不能正常運行？

Question

我的python代碼如下，但它不起作用。

import random 

secret = random.randint (1, 99) 
guess = 0 
tries = 0 

print "AHOY! I'm the Dread Pirate Oliver and I have a secret!" 
print "I will tell you where my treasure is buried if you can guess the number that I'm thinking of." 
print "It is a number from 1 to 99. I'll give you 6 tries." 

while guess != secret and tries < 6: 
    guess = input ("What's yer guess? ") 
    if guess < secret: 
     print "Too low ye scurvy dog!" 
    elif guess > secret: 
     print "Too high, landlubber!" 
    tries = tries + 1 

if guess == secret: 
    print "Avast! Ye got it! Found ma secret number, ye did!" 
    print "THE FIRST WORD IS: Awesome" 
else: 
    print "No more guesses! Better luck next time, Matey!" 
    print "Ma secret number wuz", secret 
raise SystemExit() 

import random 

secret = random.randint (1, 99) 
guess = 0 
tries = 0 

print "AHOY THERE!" 
print "ME AGAIN" 
print "I will tell you the second word if you can guess the number that I'm thinking of." 
print "It is a number from 1 to 99. I'll give you 6 tries." 

while guess != secret and tries < 6: 
    guess = input ("What's yer guess? ") 
    if guess < secret: 
     print "Too low ye scurvy dog!" 
    elif guess > secret: 
     print "Too high, landlubber!" 
    tries = tries + 1 

if guess == secret: 
    print "Avast! Ye got it! Found ma secret number, ye did!" 
    print "THE SECOND WORD IS: Land" 
else: 
    print "No more guesses! Better luck next time, Matey!" 
    print "Ma secret number wuz", secret 
raise SystemExit()  

import random 

secret = random.randint (1, 3) 
guess = 0 
tries = 0 

print "AHOY! One more thing" 
print "It is a number from 1 to 3. I'll give you 1 try." 

while guess != secret and tries < 1: 
    guess = input ("What's yer guess? ") 
    if guess < secret: 
     print "Too low ye scurvy dog!" 
    elif guess > secret: 
     print "Too high, landlubber!" 
    tries = tries + 1 

if guess == secret: 
    print "Avast! Ye got it! Found ma secret number, ye did!" 
    print "It's buried in the sand at 36 degrees North, 48 degrees east." 
else: 
    print "No more guesses! Better luck next time, Matey!" 
    print "Ma secret number wuz", secret 
raise SystemExit() 
import random 

secret = random.randint (1, 99) 
guess = 0 
tries = 0 
print "Congratz. You won!" 

在提高SystemExit（）部分中，我希望人不能夠繼續，如果他們沒有猜到最後一位。它甚至沒有開始，但是當我拿出SystemExit（）時，它可以正常工作，但它會繼續下去，即使它們沒有正確猜測。我該怎麼做才能做我想做的事？

Answer 1

此行應縮進，使其在其他區塊的一部分，否則將永遠是即使猜測是正確的執行：

raise SystemExit() 

它也可能會更好調用sys.exit()代替。

此外，如果你想要做的事了兩次，而不是複製和粘貼代碼，你應該創建一個函數並調用它兩次：

def play(): 
    # ... 

number_of_games = 2 
for i in range(number_of_games): 
    play() 

Answer 2

要退出的Python腳本，你只是想用sys.exit ：

import sys 
code = 0 
sys.exit(code) 

代碼是腳本的返回碼。如果你的腳本沒有錯誤，它應該是0，否則從1到127之間的任何數字。用戶錯誤不是腳本錯誤，所以如果你的用戶沒有猜測，只需輸入0.