致命錯誤：調用布爾型成員函數close（）

-2

您好，我有同樣的問題，但很困惑，爲什麼它不起作用。致命錯誤：調用布爾型成員函數close（）

Fatal error: Call to a member function close() on boolean in includes\register_check.php on line 45

這是$ stmt3-> close（）;

代碼

 } else { 
    if (strlen($_POST['username2']) < 2 || strlen($_POST['username2']) > 20) { 
     echo "<h3>Username must be between 2 and 20 characters!</h3>"; 
    } else { 
     $stmt = yasDB_select("SELECT `id` FROM `user` WHERE `username` LIKE '$username'"); 
     $stmt2 = yasDB_select("SELECT `id` FROM `user` WHERE `email` LIKE '$email'"); 
     if ($stmt->num_rows == 0 && $stmt2->num_rows == 0) { 
      $stmt3 = yasDB_insert("INSERT INTO `user` (`username`, `password`, `repeatpassword`, `name`, `email`, `website`, `plays`, `points`, `date`) VALUES ('$username','$password','$repeatpassword','$name','$email','$website','$plays','$points', '$date')", false); 
      if ($stmt3) { 
       echo "<h3>Registered! You may now log in.</h3>"; 
      } else { 
       $stmt3->close(); 
       echo "<h3>Registration failed!</h3>"; 
      } 
     } else { 
      $stmt->close(); 
      echo "<h3>Sorry, username or email exists. Please try again.</h3>"; 
     } 
    } 
}

來源

2016-09-26 funkstar33

我懷疑這是因爲'$ stmt3'爲空。你從else調用它，if檢查的值不是falsey。你可能想在'if'結果中找到那一行，而不是那個檢查的結果。 – Carl

Sry我的意思是$ stmt3-> close（）;這給出了錯誤。 – funkstar33

雖然你正在修復的東西，你可能還想檢查http://stackoverflow.com/questions/60174/how-can-i-prevent-sql-injection-in-php – apokryfos

 $stmt3 = yasDB_insert("INSERT INTO `user` (`username`, `password`, `repeatpassword`, `name`, `email`, `website`, `plays`, `points`, `date`) VALUES ('$username','$password','$repeatpassword','$name','$email','$website','$plays','$points', '$date')", false); 
     if ($stmt3) { 
      echo "<h3>Registered! You may now log in.</h3>"; 
     } else { 
      $stmt3->close(); 
      echo "<h3>Registration failed!</h3>"; 
     }

或許應該

 $stmt3 = yasDB_insert("INSERT INTO `user` (`username`, `password`, `repeatpassword`, `name`, `email`, `website`, `plays`, `points`, `date`) VALUES ('$username','$password','$repeatpassword','$name','$email','$website','$plays','$points', '$date')", false); 
     if ($stmt3) { 
      $stmt3->close(); 
      echo "<h3>Registered! You may now log in.</h3>"; 
     } else { 
      // $stmt3 is falsey (null or false) here, so we cant call close on it. 
      echo "<h3>Registration failed!</h3>"; 
     }

如別人，$stmt3是falsey（很可能是假的），這是什麼原因造成的Call to a member function close() on boolean錯誤，當您嘗試呼籲關閉它。

來源

2016-09-26 16:24:07 Carl

不工作已經嘗試過it.Just說註冊失敗 – funkstar33

這意味着您的查詢：yasDB_insert（「INSERT INTO用戶」（'用戶名'，'密碼'，'repeatpassword'，'name'，'email'，'網站'$ username'，'$ password'，'$ repeatpassword'，'$ name'，'$ email'，'$ website'，'$ plays' ，'$ points'，'$ date'）「，false）; - 失敗。 – Carl

是的，我說，當它說註冊失敗 – funkstar33

致命錯誤：調用布爾型成員函數close（）

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