使用PHP獲取MySQL結果？

Question

這裏絕對新手請幫忙。這是我第一次嘗試，因此不睡覺6-7個小時，無法弄清楚，所以尋求幫助。

這裏是數據庫：

CREATE TABLE `user_properties` 
(`user_id` int(11) NOT NULL, 
`username` varchar(10) NOT NULL, 
`password` varchar(10) NOT NULL, 
`firstname` varchar(20) NOT NULL, 
`property_type` varchar(50) NOT NULL, 
`property_location` varchar(50), 
`no_of_beds` int(11) NOT NULL, 
`no_of_baths` int(11) NOT NULL, 
`car_spaces` int(11) NOT NULL, 
`aditional facilities` varchar(100) NOT NULL, 
PRIMARY KEY (`user_id`)) ENGINE=MyISAM DEFAULT CHARSET=latin1 


INSERT INTO `user_properties` VALUES (1, 'john', '123456', 'John', 'house', 'strathfield Sydney NSW', '3', '2', '2', 'swimmimg pool sauna gym'); 

這裏是我正在試圖獲取：

<?php 

$host = "localhost"; // Host name 
$username = "abc_123"; // Mysql username 
$password = "123456"; // Mysql password 
$db_name = "abc_test"; // Database name 
$tbl_name = "user_properties"; // Table name 

// Connect to server and select databse. 
mysql_connect("$host", "$username", "$password")or die("cannot connect"); 
mysql_select_db("$db_name")or die("cannot select DB"); 

$con=mysqli_connect("$host", "$username", "$password"); 
// Check connection 
if (mysqli_connect_errno()) { 
echo "Failed to connect to MySQL: " . mysqli_connect_error(); 

$result = mysqli_query($con,"SELECT * FROM user_properties"); 

while($row = mysqli_fetch_array($result)) { 
    echo "<tr>"; 
    echo "<td>" . $row['property_type'] . "</td>"; 
    echo "<td>" . $row['property_location'] . "</td>"; 
    echo "<td>" . $row['no_of_beds'] . "</td>"; 
    echo "<td>" . $row['no_of_baths'] . "</td>"; 
    echo "<td>" . $row['car_spaces'] . "</td>"; 
    echo "</tr>"; 
} 

mysqli_close($con); 
?> 

Answer 1

<?php 
$link = mysql_connect('localhost', 'root', ''); 
if (!$link) 
{ 
    die('Could not connect: ' . mysql_error()); 
} 
echo 'Connected successfully'; 


$db_selected = mysql_select_db('abc_test', $link); 
if (!$db_selected) 
{ 
    die ('Can\'t use database name : ' . mysql_error()); 
} 

$result = mysql_query("SELECT * FROM user_properties"); 


while($row = mysql_fetch_array($result)) 
{ 
    echo "<tr>"; 
    echo "<td>" . $row['property_type'] . "</td>"; 
    echo "<td>" . $row['property_location'] . "</td>"; 
    echo "<td>" . $row['no_of_beds'] . "</td>"; 
    echo "<td>" . $row['no_of_baths'] . "</td>"; 
    echo "<td>" . $row['car_spaces'] . "</td>"; 
    echo "</tr>"; 
} 


mysql_close($link); 

?> 

試試這個

Answer 2

試試這個

//you have to change database name, password and other database info 

<?php 

$host = "localhost"; // Host name 
$username = "root"; // Mysql username 
$password = ""; // Mysql password 
$db_name = "nes"; // Database name 
$tbl_name = "user_properties"; // Table name 

// Connect to server and select databse. 
$con= mysqli_connect($host, $username, $password, $db_name); 
// Check connection 
if (mysqli_connect_errno()) { 
echo "Failed to connect to MySQL: " . mysqli_connect_error(); 
} 
$result = mysqli_query($con,"SELECT * FROM user_properties"); 
echo '<table border=1px solid black>'; 
while($row = mysqli_fetch_array($result)) { 
    echo "<tr>"; 
    echo "<td>" . $row['property_type'] . "</td>"; 
    echo "<td>" . $row['property_location'] . "</td>"; 
    echo "<td>" . $row['no_of_beds'] . "</td>"; 
    echo "<td>" . $row['no_of_baths'] . "</td>"; 
    echo "<td>" . $row['car_spaces'] . "</td>"; 
    echo "</tr>"; 
} 
echo '</table>'; 
mysqli_close($con);