Jbuilder：我如何合併2個頂級數組？

Question

我有兩個頂級數組，它們具有相同的格式。我想將它們合併：

json = Jbuilder.encode do |json| 
    json.(companies) do |json, c| 
    json.value c.to_s 
    json.href employee_company_path(c) 
    end 
    json.(company_people) do |json, cp| 
    json.value "#{cp.to_s} (#{cp.company.to_s})" 
    json.href employee_company_path(cp.company) 
    end 
end 

所以輸出將如下所示："[{value: "a", href: "/sample1"}, {value: "b", href: "/sample2"}]"

但上面的代碼不起作用。它只包括第二個陣列："[{value: "b", href: "/sample2"}]"

有人可以幫助我嗎？提前致謝。

Answer 1

result = [] 
companies.each do |c| 
    result << {:value => c.to_s, :href => employee_company_path(c) 
end 
company_people.each do |c| 
    result << {:value => "#{cp.to_s} (#{cp.company.to_s})", :href => employee_company_path(cp.company) 
end 
# at this point result will be an array of companies and people which just needs converting to json. 
result.to_json 

Answer 2

我知道有兩種選擇：

def Employee 
    def company_path 
    self.company.company_path if self.company 
    end 
end 

[...] 

combined = (companies + company_people).sort_by{ |c| c.value } 
# Do other things with combined 

json.array!(combined) do |duck| 
    json.value(duck.to_s) 
    json.href(duck.company_path) 
end 

或者當你有：

1. 迭代，這與鴨的多源陣列行之有效前合併陣列鴨子和火雞，結合json陣列：

   company_json = json.array!(companies) do |company| 
       json.value(company.to_s) 
       json.href(employee_company_path(company)) 
   end 
   
   people_json = json.array!(company_people) do |person| 
       json.value(person.to_s) 
       json.href(employee_company_path(person.company)) 
   end 
   
   company_json + people_json 
   

在這兩種情況下，都不需要調用#to_json或類似的函數。

Answer 3

尤里的回答讓我親近，但對我來說最終的解決方案只是在我的.jbuilder文件中做這個。

json.array!(companies) do |company| 
    json.value(company.to_s) 
    json.href(employee_company_path(company)) 
end 

json.array!(company_people) do |person| 
    json.value(person.to_s) 
    json.href(employee_company_path(person.company)) 
end 

我把數組放入的順序是數組合成的順序。