如何使兩個NSDictionary或NSMutableDictionary與值相交？

Question

想要合併兩個NSDictionary或NSMutableDictionary只與dict1值。如[NSMutableDictionary addEntriesFromDictionary:]和intersectSet（來自NSMutableSet）。

Dict 1 = @{@」One」: @」」, @」Two」: @」"} 

Dict 2 = @{@」One」: @」1」, @」Two」: 2, @」Three」: @」3"} 

我期待合併後的輸出= @ {@」一」：@」 1」 ，@」二」：@」 2" }

UPDATE

我已經嘗試過與此[Dict1 addEntriesFromDictionary:Dict2]人給答案@{@」One」: @」1」, @」Two」: 2, @」Three」: @」3"}

我也是試着用NSMutableSet

NSMutableSet *keysInA = [NSMutableSet setWithArray:tempDict.allKeys]; 
NSSet *keysInB = [NSSet setWithArray:tempDict1.allKeys]; 
[keysInA intersectSet:keysInB]; 
NSLog(@"keys in A that are not in B: %@", keysInA); 

這一個給出One, Two, Three。

因此[NSMutableSet setWithArray:]和[NSMutableDictionary addEntriesFromDictionary:]不會給我所期望的。

如果上面的代碼有任何工作讓我清楚。謝謝。

Answer 1

NSDictionary *dict1 = @{@"One": @"", @"Two": @"6"}; 

NSDictionary *dict2 = @{@"One": @"1", @"Two": @"2", @"Three": @"3"}; 

NSDictionary * dict = [dict2 dictionaryWithValuesForKeys:[dict1 allKeys]]; 

NSLog(@"dict %@",dict); 

// Log value 
dict { 
One = 1; 
Two = 2; 
} 

這裏我所期待的。

Answer 2

試試這個...

//Assuming both dictionaries have same kind of keys 
NSMutableDictionary *dict1 = @{@"One" : @"", @"Two": @"", @"Three" : @""}.mutableCopy; 
NSDictionary *dict2 = @{@"One" : @"1", @"Two": @"2", @"Three" : @"3",@"Four":@"4"}; 

for (NSString *key in dict1.allKeys) 
{ 
    if (dict2[key]) 
    { 
     dict1[key] = dict2[key]; 
    } 
} 
NSLog(@"Updated dict %@",dict1);