Symfony FosRest使用終點api

我需要在我的動作中調用一些方法（GET，POST或PUT），這是怎麼回事。示例I具有PUT端點Symfony FosRest使用終點api

/** 
* Update existing Team from the submitted data or create a new Team. 
* 
* @ApiDoc(
* resource = true, 
* description = "Create/Update single Team", 
* parameters={ 
*  {"name"="name", "dataType"="string", "required"=false, "description"="image_back"} 
* }, 
* statusCodes = { 
*  200 = "Team successful update", 
*  400 = "Secret token is not valid" 
* }, 
* section="Team" 
*) 
* @RestView() 
* 
* @param Request $request 
* @param int  $id 
* 
* @return View 
*/ 
public function putTeamAction(Request $request, $id)

並且此端點具有路由「put_team」。如何調用這個動作在另一個控制器，比如我叫POST實體鉛和在這個崗位鉛我需要調用「put_team」：

/** 
* Post Lead. 
* 
* @ApiDoc(
* resource = true, 
* description = "Post lead", 
* parameters={ 
*  {"name"="title", "dataType"="string", "required"=true, "description"="title lead"}, 
* statusCodes = { 
*  200 = "Returned when successful", 
*  400 = "Returned secret token is not valid" 
* }, 
* section="Lead" 
*) 
* 
* @RestView() 
* 
* @param Request $request 
* 
* @return View 
* 
* @throws NotFoundHttpException when not exist 
*/ 
public function postLeadAction(Request $request) 
{

如果我試試這個

return $this->redirect($this->generateUrl('put_team', array('id' => 31)));

但調用get方法， bacause網址獲取和放置平等，也許是因爲在默認情況下GET方法重定向

但我不需要回報，我需要調用一些潰敗並在第一個動作仍能正常工作，使用的答案被潰敗「put_eam」我嘗試

$test = $this->redirect($this->generateUrl('put_team', array('id' => 31)));

，但有狀態碼302和

內容的HTML

有：

<body> 
    Redirecting to <a href="/app_dev.php/api/teams/31">/app_dev.php/api/teams/31</a>. 
</body>

我用這一點，但如何像這樣的幫助狂飲使用？

function send_messages_aog($senders_token, $id, $title){ 

$url = BASE_URL.'/api/teams/'.$id; 

$data = array('senders_token' => $senders_token, 'title' => $title); 

$options = array(
    'http' => array(
     'method' => 'PUT', 
     'content' => json_encode($data), 
     'header'=> "Content-Type: application/json\r\n" . 
      "Accept: application/json\r\n" 
    ) 
); 

$context = stream_context_create($options); 
$result = file_get_contents($url, false, $context); 
$response = json_decode($result); 

return $response; 
}

解決

我用狂飲

public function updateTalent($userId, $token) 
{ 
    $guzzle = new Client(); 
    $putTeam = $guzzle 
     ->put($this->router->generate('put_developer', ['id' => $userId], UrlGeneratorInterface::ABSOLUTE_URL), 
      [], 
      json_encode([ 
       "token" => $token, 
      ]) 
     ) 
     ->send() 
     ->getBody(true); 
    $answer = json_decode($putTeam, true); 
    return $answer; 
}

來源

2016-01-24 shuba.ivan

你可以做HTTP請求與PHP cURL或安裝PHP HTTP客戶端就像Guzzle。

來源

2016-01-25 19:37:04

我更新我的問題，如何使用Guuzzle就像我使用file_get_contents？ –

Symfony FosRest使用終點api

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