我是Django的初學者，面臨着urls.py的語法錯誤

Question

這是我的個人/ urls.py。我一直在試圖解決這個問題好幾天。我知道這肯定是一個非常愚蠢的錯誤，但不勝感激。

from django.conf.urls import url, include 
from . import views 
urlpatterns = [ 
    url(r'^$',views.index, name='index'), 
    url(r'contact/',views.contact, name='contact') 
    url(r'about/',views.about, name='about') 
] 

這裏是views.py

def index(request): 
    return render(request, 'personal/home.html') 

def contact(request): 
    return render(request, 'personal/basic.html', {'content':['https://www.facebook.com/arjunkashyap30']}) 

def about(request): 
    return render(request, 'personal/about.html', {'content': ["This is an abut 
page"]}) 

Answer 1

您在定義每個端點的最終忘記comma。

urlpatterns = [ 
    url(r'^$',views.index, name='index'), 
    url(r'contact/',views.contact, name='contact'), 
    url(r'about/',views.about, name='about'), 
]