如何申請grepl數據幀

Question

SOLUTION：

發佈者@docendodiscimus：「嘗試的sapply環比模式：

sapply(df_triggers$trigger, grepl, df_sen$sentence)" 

最初的問題：

我想用grepl用於定義爲數據幀的多個模式 df_sen表示爲

sentence 
"She would like to go there" 
"I had it few days ago" 
"We have spent few millions" 

個df_triggers現分述如下：

trigger 
few days 
few millions 

我想創建一個矩陣，其中一句X觸發器和在路口看到1，如果觸發是在一個句子中發現和0，如果事實並非如此。

我試圖做這樣的：

df_sen = read.csv("df.csv", sep = ";",header = TRUE) 
df_triggers = read.csv("df.csv", sep = ";",header = TRUE) 
dat <- data.frame(v=df_sen$sentence) 
matrix <- grepl(df_triggers$trigger, dat$v) 
write.csv(matrix,file = "matrix.csv") 

但我看到，我在grepl超過1種模式（）的錯誤信息。

所需的輸出是：

        few days few millions 
"She would like to go there"  0    0 
"I had it few days ago"    1    0 
"We have spent few millions   0    1 

你能幫我達成這樣的結果嗎？

Answer 1

sapply(df_triggers$trigger, grepl, df_sen$sentence) 

從@docendodiscimus工作。