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我想弄清楚如何在另一個準備好的staments循環中運行第二個準備好的語句。不是最佳的,但不知道我還能怎麼解決這個...準備好的語句嵌套在另一個準備的語句
這裏就是我想:
$stmt = $mysqli->stmt_init();
### GET THE CURRENT USERS FRIENDS ###
$sql = "SELECT f.fk_user_id2
, u.username
, u.profileimg FROM ".$prefix."_friends f
INNER JOIN ".$prefix."_users u
ON f.fk_user_id2 = u.id
WHERE f.fk_user_id1 = ? ORDER BY u.username ASC";
if($stmt->prepare($sql)){
$stmt->bind_param('i',$playerid);
$stmt->execute();
$stmt->bind_result($userPoints);
while ($stmt->fetch()){
$friendid = $row1['fk_user_id2'];
$friendname = $row1['username'];
if(empty($row1['profileimg'])){
$profileimg = 'http://duefmun.dk/profileimages/noimage.png';
} else {
$profileimg = 'http://duefmun.dk/profileimages/'.$row1['profileimg'];
}
### GET THE HISTORY ###
$sql1 = mysql_query("SELECT wins, games FROM ".$prefix."_newversus WHERE fk_player=? AND fk_opponent=?");
if($stmt->prepare($sql1)){
$stmt->bind_param('ii',$playerid,$friendid);
$stmt->execute();
$stmt->bind_result($wins,$games);
$stmt->fetch();
if($games == 0){
$history = $languagestring[165];
} else {
$history = $languagestring[168].' '.$wins.' '.$languagestring[169].' '.$games.' '.$languagestring[170];
}
}
$string .= $friendname.','.$friendid.','.$history.','.$profileimg.'^';
}
}
$string = substr($string,0, (strlen($string)-1));
echo $string.'%';
$stmt->close();
也許有可能innerjoin第二個語句,但不知道怎麼樣。請幫忙在此先感謝: -/
爲什麼'朋友'和'newversus'綁定到表名?這相當於使用關係數據庫的目的。 – ethrbunny 2013-02-10 13:02:48