銷售數據庫中有3個表格:orders(order_id, user_id, item_id, quantity, date), users(user_id, name, discount_percent) and items(item_id, name, type, price)
。我試圖生成每月的利潤由用戶分組的報表按天數必須看這個(片段):準備好的語句語法錯誤
|-------user--------|----------day_1--------|---------day_2---------|---------day_3---------| etc. |
|-user_name_1-|-sum_of_expenses-|-sum_of_expenses-|-sum_of_expenses-| etc. |
|-user_name_2-|-sum_of_expenses-|-sum_of_expenses-|-sum_of_expenses-| etc. |
我用下面的準備語句來實現:
SELECT
GROUP_CONCAT(DISTINCT CONCAT('SUM(IF(DATE(orders.date) = \'',
DATE(orders.date),
'\', orders.quantity * items.price * (1 - users.discount_percent/100), 0)) AS ',
DATE(orders.date))
ORDER BY DATE(orders.date))
INTO @sql FROM
orders;
SET @sql = CONCAT('SELECT users.name, ', @sql, ' FROM
users
INNER JOIN
orders ON users.user_id = orders.user_id
INNER JOIN
items ON orders.item_id = items.item_id
GROUP BY users.name
ORDER BY users.user_id');
PREPARE statement FROM @sql;
EXECUTE statement;
DEALLOCATE PREPARE statement;
對於由於某種原因,它給了我一個警告:
1 row(s) affected, 1 warning(s): 1260 Row 8 was cut by GROUP_CONCAT()
然後一個錯誤:
Error Code: 1064. You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '2015-01-01,SUM(IF(DATE(orders.date) = '2015-01-02', orders.quantity * items.pric' at line 1
我認爲這與日期或引號的格式有關,但是爲了解決問題而輸入的內容都失敗了。
另外我想弄清楚如何通過php的mysqli prepare()方法實現這個複雜的語句。
我不認爲'SELECT ... INTO'變量將直接工作在MySQL。但是,爲什麼在給它分配一些東西后立即覆蓋'@ sql'? –