0
是否有可能從計算只保留最後X位這樣?:保持特定位從計算
a_register <= some_addr - {some_addr[(width-1):limit],limit{1'b0}}
//can it be done in one line of code? Like:
//a_register <= some_addr - {some_addr[(width-1):limit],limit{1'b0}} [X:0]