選擇運動員數據的MySQL數據庫需要位置

Question

我從數據庫中選擇數據並將其顯示在頁面上。
未保存在數據庫中的一個有用值是$position。 顯示每個運動員的位置很有用，這裏顯示的數字只是顯示增加的$i值。

代碼如下ORDERS BY run points。問題是，當按照其他事物排序列表時，例如ORDER BY athlete ASC，分配給每個運動員的位置不隨運動員移動。

$selectproduct = mysqli_query($link, "SELECT `athlete`,`reference`,SUM(`Run Points`) AS 'Run Points',COUNT(`eventID`) AS 'num_runs',`Volunteer Points`,`location`,`Gender pos` FROM `Events` WHERE `Gender`='$Gender' AND `location`='$location' GROUP BY `reference` ORDER BY `Run Points` DESC"); 


while ($rowGetDetails = mysqli_fetch_array($selectproduct)){ 

$reference=$rowGetDetails['reference']; 
$athlete=$rowGetDetails['athlete']; 
$points=$rowGetDetails['Run Points']; 
$num_runs=$rowGetDetails['num_runs']; 
$position=$i; 

echo '<tr>'; 
echo'<td>'; 
echo $athlete; 
echo '</td>'; 
echo'<td>'; 
echo $num_runs; 
echo '</td>'; 
echo'<td>'; 
echo $points; 
echo '</td>'; 
echo '</tr>'; 

$i=$i+1; 
} 

當別的東西排序，如athlete ASC在$selectproduct它仍然給$postition作爲該列表中的第一位運動員與一個名稱數量1一開始的時候，是不是得分最多運動員。

還有其他選項$selectproduct如下面通過athlete ASC排序：

$selectproduct = mysqli_query($link, "SELECT `athlete`,`reference`,SUM(`Run Points`) AS 'Run Points',COUNT(`eventID`) AS 'num_runs',`Volunteer Points`,`location`,`Gender pos` FROM `Events` WHERE `Gender`='$Gender' AND `location`='$location' GROUP BY `barcode` ORDER BY `athlete` ASC" 

Answer 1

只要分配$ i值外循環;

$selectproduct = mysqli_query($link, "SELECT `athlete`,`reference`,SUM(`Run Points`) AS 'Run Points',COUNT(`eventID`) AS 'num_runs',`Volunteer Points`,`location`,`Gender pos` FROM `Events_08052017_withdate` WHERE `Gender`='$Gender' AND `location`='$location' GROUP BY `reference` ORDER BY `Run Points` DESC"); 
    $i = 1; 

    while ($rowGetDetails = mysqli_fetch_array($selectproduct)){ 

    $reference=$rowGetDetails['reference']; 
    $athlete=$rowGetDetails['athlete']; 
    $points=$rowGetDetails['Run Points']; 
    $num_runs=$rowGetDetails['num_runs']; 
    $position=$i; 

    echo '<tr>'; 
    echo'<td>'; 
    echo $athlete; 
    echo '</a>'; 
    echo '</td>'; 
    echo'<td>'; 
    echo $num_runs; 
    echo '</td>'; 
    echo'<td>'; 
    echo $points; 
    echo '</td>'; 
    echo '</tr>'; 

    $i=$i+1; 
    } 

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