查找字典中的所有常用值和子常用值

Question

我是在python中使用dicitonaries的新功能。我手邊有一個簡單的問題。我有一個名爲「輸入」的口號。

Input={'VAR1':['K1','K2','K3','K4','K5...'], 
'VAR2':['K3','K4',...], 
'VAR3':['K2','K4','K5',...]} 

詞典「輸入」中的鍵數量可能會有所不同。我渴望的輸出是讓所有常用值的列表，我想獲得小組共同價值觀作爲字典

'K4' string common in all the lists (for all key values) 
'K3' is only present in the list with key'VAR1' and 'VAR2'. 

所以它幫助，如果我有相應的鍵

輸出：

Common_Value=['K4',....] 

Subcommon_Values1=['VAR1':['K3....'],'VAR2':['K3....']] 
Subcommon_values2=['VAR1':['K5',...],'VAR3':['K5',....]] 

任何人都可以幫助我嗎？

謝謝

Answer 1

這將讓你所有的共同的價值觀：

sect = None 
for k,v in Input.items(): 
    if sect == None: 
     sect = set(v) 
    else: 
     sect = sect.intersection(set(v)) 
Common_Value = list(sect) 

直到你清楚你的不同SubCommonValues結果和他們的實際結構（你似乎有列表中的鍵）之間的差異，不能確定這是你想不想要的：

all = None 
for k,v in Input.items(): 
    if all == None: 
     all = set(v) 
    else: 
     all = all.union(set(v)) 
diff = all.difference(sect) 
uncom = { x:list() for x in diff } 
for x in diff: 
    for k,v in Input.items(): 
     if x in v: 
      uncom[x].append(k) 
grps = {} 
for k,v in uncom.items(): 
    kv = tuple(v) 
    if kv not in grps: 
     grps[kv] = [k] 
    else: 
     grps[kv].append(k) 
for k,v in grps.items(): 
    print({ x:v for x in k }) 

Answer 2

，你可以這樣做：

result=[i for i in Input if "K4" in Input[i]] 

例子：

>>> Input={'VAR1':['K1','K2','K3','K4','K5'],'VAR2':['K3','K5'],'VAR3':['K2','K4','K5']} 
>>> result=[i for i in Input if "K4" in Input[i]] 
>>> result 
['VAR1', 'VAR3'] 

編輯：

也許是這樣的：

commonValues=['K4', 'K2'] 
result=[i for i in Input if set(commonValues).issubset(set(Input[i]))] 

這將返回key列表中你Inputdict包含commonValues列表的所有元素...