如何計算生成的隨機數的平均數量？

Question

我已經寫了一個FOR循環來調用一個函數100次以獲得100個隨機數，我現在需要計算所有生成的隨機數的平均數。我怎樣才能做到這一點？這是我站起身來，到目前爲止

import random 

num1 = int(input("Input First number ")) 
num2 = int(input("Input Second number ")) 

for i in range(10): 
    print(random.uniform(num1, num2), end = "\t") 

Answer 1

首先，你的函數只正在運行的10倍。您需要存儲您生成的值，而不是將它們打印到屏幕上。您可以通過將其存儲在列表中來完成此操作。

要獲得100個隨機變量的列表，你可以做[random.uniform(num1, num2) for i in range(100)]。

然後，你需要找到這個的平均值。要獲得總金額，您可以做sum(list)。要獲取值的數量，請執行len(list)。如果我們結合這一切一起，我們得到：

import random 

num1 = int(input("Input First number: ")) 
num2 = int(input("Input Second number: ")) 

random_numbers = [random.uniform(num1, num2) for i in range(100)] 
print(sum(random_numbers)/len(random_numbers)) 

輸出是：

>>> import random 
>>> num1 = int(input("Input First number: ")) 
Input First number: 10 
>>> num2 = int(input("Input Second number: ")) 
Input Second number: 20 
>>> random_numbers = [random.uniform(num1, num2) for i in range(10)] 
>>> random_numbers 
[13.083389212287019, 12.551686149990369, 13.881302022239865, 12.5156539109837, 12.340949073439575, 13.693758114264867, 13.972147752101735, 14.111313446849902, 11.693700678679372, 18.136716333128035] 
>>> print(sum(random_numbers)/len(random_numbers)) 
13.5980616694 

Answer 2

import random 
rand_nums = [random.uniform(num1, num2) for i in range(10)] 
average = sum(rand_nums)/len(rand_nums) 

或者，如果你喜歡使用numpy

import numpy as np 
rand_nums = np.random.uniform(num1,num2,10) 
average = rand_nums.mean() 

Answer 3

我認爲你必須存儲一些數字，而不是打印出來。如果您使用列表，則可以計算總和，然後除以長度。

import random 

num1 = int(input("Input First number ")) 
num2 = int(input("Input Second number ")) 

numbers = [] 
for i in range(10): 
    numbers.append(random.uniform(num1, num2)) 

print(numbers) 
print(sum(numbers)/len(numbers)) 

Answer 4

這是很基本的東西，希望這有助於：

所有的

import random 
num1 = int(input("Input First number ")) 
num2 = int(input("Input Second number ")) 

sum = 0 
numbers = 100 
for i in range(numbers): 
    random_number = random.uniform(num1, num2) 
    sum += random_number 
avarage = sum/numbers 
print(avarage)