計算多個隨機數的平均值Python

Question

我對Python相當陌生，遇到了一個試圖計算一堆隨機數的平均值的障礙。該程序的總體概述是它是一個模具滾動程序它會提示用戶輸入一定數量的邊，然後滾動，直到程序輸出蛇眼。它也跟蹤雙打的數量和獲得蛇眼需要多長時間。然後創建整個程序中每個骰子的平均數量。這是我迷失的地方。

編輯：我刪除了我的原代碼，並在瓦西利斯的回答工作：

import random 

while True: 
    #prompts user for valid number 
    user_s = int (input ("How many sides on your dice? ")) 
    if user_s < 3: 
     print("That is not a valid size value, please enter a positive number") 
    if user_s >= 3: 
     break 

print() 
print("Thanks! Here we go...") 
print() 
double_count = 0 
roll_count = 0 

sum1 = 0 # Used to calculate sum of die_1 
sum2 = 0 # Used to calculate sum of die_2 

while True: 
    roll_count += 1 
    die_1 = random.randint(1,user_s) 
    die_2 = random.randint (1,user_s) 




    print(roll_count,".", " Die number 1 is ", die_1 , " and die number 2 is ", die_2, ".", sep ="") 
    if die_1 == die_2: 
     double_count += 1 
    if die_1 == 1 and die_2 == 1: 
     break 

    # Making sum 
    sum1 = sum1 + die_1 
    sum2 = sum2 + die_2 

print("You finally got snake eyes on try number", roll_count) 
print("Along the way you rolled a double", double_count,"times") 

print(die_1) 
print(die_2) 

# Integer divisions 

avg_roll1 = sum1 // roll_count 
avg_roll2 = sum2 // roll_count 


print("The average roll for die 1 was", format(avg_roll1,".2f")) 
print("The average roll for die 2 was", avg_roll2) 

但是像他指出，它並不需要全部通過所有的卷記錄的數字，而不是最後的數字。 任何幫助來實現這一點，將不勝感激。

謝謝！

Answer 1

明白了自己。

將累加器變量=設置爲模具卷。在這種情況下，sum1和sum2是變量。

# make all of the functions in the "random" module available to this program 
import random 

while True: 
    #prompts user for valid number 
    user_s = int (input ("How many sides on your dice? ")) 
    if user_s < 3: 
     print("That is not a valid size value, please enter a positive number") 
    if user_s >= 3: 
     break 

print() 
print("Thanks! Here we go...") 
print() 
double_count = 0 
roll_count = 0 

sum1 = 0 # Used to calculate sum of die_1 
sum2 = 0 # Used to calculate sum of die_2 

#while statement for die rolls 
while True: 
    roll_count += 1 
    die_1 = random.randint(1,user_s) 
    sum1 += die_1 

    die_2 = random.randint (1,user_s) 
    sum2 += die_2 




    print(roll_count,".", " Die number 1 is ", die_1 , " and die number 2 is ", die_2, ".", sep ="") 
    if die_1 == die_2: 
     double_count += 1 
    if die_1 == 1 and die_2 == 1: 
     break 



print("You finally got snake eyes on try number", roll_count) 
print("Along the way you rolled a double", double_count,"times") 


# Integer divisions 

avg_roll1 = sum1/roll_count 

avg_roll2 = sum2/roll_count 


print("The average roll for die 1 was", format(avg_roll1,".2f")) 
print("The average roll for die 2 was", format(avg_roll2,".2f")) 

Answer 2

如果您喜歡看一看，我在代碼中做了一些更改。我認爲你想要把平均值作爲整數來計算，儘管你可以改變它。您可以使用die_1和die_2簡單整型變量，因此它們只持有由random.randint(1,user_s)產生的最後一個值：

import random 

    '''Skipped input part''' 

    print() 
    print("Thanks! Here we go...") 
    print() 
    double_count = 0 
    roll_count = 0 

    sum1 = 0 # Used to calculate sum of die_1 
    sum2 = 0 # Used to calculate sum of die_2 

    while True: 
     roll_count += 1 
     die_1 = random.randint(1,user_s) 
     die_2 = random.randint (1,user_s) 

     print("DIE_1: ", die_1) 
     print("DIE_2: ", die_2) 


     print(roll_count,".", " Die number 1 is ", die_1 , " and die number 2 is ", die_2, ".", sep ="") 
     if die_1 == die_2: 
      double_count += 1 
     if die_1 == 1 and die_2 == 1: 
      break 

     # Making sum 
     sum1 = sum1 + die_1 
     sum2 = sum2 + die_2 

    print("You finally got snake eyes on try number", roll_count) 
    print("Along the way you rolled a double", double_count,"times") 

    print(die_1) 
    print(die_2) 

    # Integer divisions 

    avg_roll1 = sum1 // roll_count 
    avg_roll2 = sum2 // roll_count 


    print("The average roll for die 1 was", avg_roll1) 
    print("The average roll for die 2 was", avg_roll2)