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我正在使用下面的查詢來拉出一個賬戶列表和隨附的可選代碼。每個帳戶有95個代碼,而不僅僅是我在下面的結果中顯示的2個代碼。在沒有PIVOT的情況下在(RAPID)SQL中創建行到列
SELECT DISTINCT Ref1.ACCOUNT_ID as Acct_Numb,
Current_Date as DATA_DATE,
Cat.OPTIONAL_CTGRY_CD As Code,
Cat.OPTIONAL_CTGRY_CD || ' - ' || Cat.OPTIONAL_CTGRY_NM AS Code_Combo,
Class.OPTIONAL_CLASS_CD as Code_Answer,
Class.OPTIONAL_CLASS_NM as Code_Answer_Desc
FROM xxxxx.zzzzzz_OPT_REF Ref1
LEFT JOIN xxxxx.zzzzzz_OPT_CATEGORY Cat
ON xxxxx.zzzzzz_OPT_REF.OPTIONAL_CTGRY_CD = xxxxx.zzzzzz_OPT_CATEGORY.OPTIONAL_CTGRY_CD
LEFT JOIN xxxxx.zzzzzz_OPT_CLASS Class
ON xxxxx.zzzzzz_OPT_REF.OPTIONAL_CLASS_CD = xxxxx.zzzzzz_OPT_CLASS.OPTIONAL_CLASS_CD
AND xxxxx.zzzzzz_OPT_CATEGORY.OPTIONAL_CTGRY_CD = xxxxx.zzzzzz_OPT_CLASS.OPTIONAL_CTGRY_CD
LEFT JOIN xxxxx.HRTVACT_PCS Acct
ON xxxxx.ACCOUNT_ID = Acct.ACCOUNTID
WHERE xxxxx.ACCOUNTSTATUS = 'OPEN' AND xxxxx.ACCOUNTID = '123456' OR xxxxx.ACCOUNTID = '654321'
ORDER BY ACCT_NUMB ASC, CODE ASC;
下面是結果
DATA_DATE ACCT_NUMB CODE CODE_COMBO CODE_ANSWER CODE_ANSWER_DESC
11/8/2016 123456 1 1 - Reporting 0 NOT APPLICABLE
11/8/2016 123456 2 2 - System 4 SYSTEM 2
11/8/2016 654321 1 1 - Reporting 3 APPLIED
11/8/2016 654321 2 2 - System 3 N/A
我需要創建,將結果作爲類似於下表中的數據透視表。
(CODE) (CODE_COMBO) (CODE) (CODE_COMBO)
DATA_DATE ACCT_NUMB 1 1 - Reporting 2 2 - System
11/8/2016 123456 0 NOT APPLICABLE 4 SYSTEM 2 (CODE_ANSWER)/(CODE_ANSWER_DESC)
11/8/2016 654321 3 APPLIED 3 N/A (CODE_ANSWER)/(CODE_ANSWER_DESC)
我以前沒有嘗試這樣做,我難倒