使用MySQL和PHP創建過濾功能

Question

嘿，這裏是我的問題，我正在使用SQL查詢來嘗試返回基於帖子元數據的結果。這個元數據是用戶在用戶界面創建後創建的。我遇到了一個過濾器問題，它一次只能處理一個變量，但不超過這個範圍（例如：如果主題被選中，它可以正常工作，但是如果選擇了主題AND介質，它將不返回結果），這裏是代碼：

$db_build_post_filter_WHERE = array(); 
// Default to avoid errors on WHERE GROUP BY 
$db_build_post_filter_WHERE [] = 'cmsp_post.post_id > 0'; 
//$db_build_post_filter_WHERE [] = 'cmsp_post.post_id = cmsp_post_meta.post_id'; 
if (isset($gnocore_cmsp_build_topic_slug_id_array[$filter_topic])) { 
    $db_build_post_filter_WHERE [] = 'post_meta_key = "topic_id" AND post_meta_value = ' . $gnocore_cmsp_build_topic_slug_id_array[$filter_topic]; 
} 
if (isset($gnocore_cmsp_build_media_slug_id_array[$filter_media])) { 
$db_build_post_filter_WHERE [] = 'post_meta_key = "media_id" AND post_meta_value = ' . $gnocore_cmsp_build_media_slug_id_array[$filter_media]; 
} 
if (isset($gnocore_cmsp_build_author_slug_id_array[$filter_author])) { 
$db_build_post_filter_WHERE [] = 'post_meta_key = "author_id" AND post_meta_value = ' . $gnocore_cmsp_build_author_slug_id_array[$filter_author]; 
} 

// PROJECT FILTER ARRAY 
$build_post_filter_array = array(); 
gnoshare_db_select ('cmsp_post LEFT JOIN cmsp_post_meta ON cmsp_post.post_id = cmsp_post_meta.post_id','cmsp_post.post_id',implode(' AND ',$db_build_post_filter_WHERE) . ' GROUP BY cmsp_post.post_id','cmsp_post.project_id, post_name, cmsp_post.post_id','db_build_post_filter_array_num','db_build_post_filter_array_results'); 
if ($db_build_post_filter_array_num > 0) { 
    foreach ($db_build_post_filter_array_results as $db_build_post_filter_array_result) { 
     $build_post_filter_array [$db_build_post_filter_array_result->post_id] = ''; 
    } 
} 

我相信我的問題是在「PROJECT FILTER ARRAY」部分，如果有人可以協助它，將不勝感激。

乾杯

編輯：改變「和」 to「或」生成的簡單顯示所有帖子的結果，我認爲這是公平地說，我的問題就出在這行代碼，但是我仍然找不到一種方法來生成我正在尋找的結果。

gnoshare_db_select ('cmsp_post LEFT JOIN cmsp_post_meta ON cmsp_post.post_id = cmsp_post_meta.post_id','cmsp_post.post_id',implode(' OR ',$db_build_post_filter_WHERE) . ' GROUP BY cmsp_post.post_id','cmsp_post.project_id, post_name, cmsp_post.post_id','db_build_post_filter_array_num','db_build_post_filter_array_results'); 

編輯：這裏是我的表（大約）：

+----------+---------------+-----------------+ 
| post_id | post_meta_key | post_meta_value | 
+----------+---------------+-----------------+ 
|  1 | topic_id |  1  | 
+----------+---------------+-----------------+ 
|  1 | media_id |  1  | 
+----------+---------------+-----------------+ 
|  1 | author_id |  2  | 
+----------+---------------+-----------------+ 
|  2 | media_id |  2  | 
+----------+---------------+-----------------+ 
|  2 | topic_id |  2  | 
+----------+---------------+-----------------+ 

，我想它的基礎上的選擇的用戶已作出後（例如過濾：用戶選定的主題1 ，媒體1和作者2的帖子1和媒體2的帖子2和帖子2的帖子2 （如上表））假設這個例子是真的，我希望我的網頁生成後一個，如果任何以下內容被過濾器選中：按主題過濾1僅顯示帖子1，按主題1過濾，媒體1僅顯示帖子1，按主題過濾1媒體2將顯示一條消息，指出與所選條件沒有匹配，依此類推。這是否澄清了一點？

Answer 1

如果我沒有錯，你應該在過濾器之間使用OR並用（）括起來。例如：

$db_build_post_filter_WHERE [] = '(cmsp_post.post_id > 0)'; 
if (isset($gnocore_cmsp_build_topic_slug_id_array[$filter_topic])) { 
    $db_build_post_filter_WHERE [] = '(post_meta_key = "topic_id" 
            AND post_meta_value = ' . 
       $gnocore_cmsp_build_topic_slug_id_array[$filter_topic].')'; 
} 
if (isset($gnocore_cmsp_build_media_slug_id_array[$filter_media])) { 
    $db_build_post_filter_WHERE [] = '(post_meta_key = "media_id" 
            AND post_meta_value = ' . 
       $gnocore_cmsp_build_media_slug_id_array[$filter_media].')'; 
} 
//Other conditions 

// PROJECT FILTER ARRAY 
$build_post_filter_array = array(); 
gnoare_db_select ('cmsp_post 
        LEFT JOIN cmsp_post_meta 
          ON cmsp_post.post_id = cmsp_post_meta.post_id', 
       'cmsp_post_post.post_id', 
       implode(' OR ',$db_build_post_filter_WHERE) . 
       ' GROUP BY cmsp_post.post_id','cmsp_post.project_id, post_name, cmsp_post.post_id','db_build_post_filter_array_num','db_build_post_filter_array_results');