Python的簡化if語句邏輯

Question

我有，我有if語句學習Python中使用的情況下：

if ([Team1_matches[0]>Team2_matches[0] and Team1_matches[1]>Team2_matches[1] and Team1_matches[2]>Team2_matches[2] and 
Team1_matches[3]>Team2_matches[3] and Team1_matches[4]>Team2_matches[4]]): 
winner="Team 1" 
elif ([Team2_matches[0]>Team1_matches[0] and Team2_matches[1]>Team1_matches[1] and Team2_matches[2]>Team1_matches[2] and 
    Team2_matches[3]>Team1_matches[3] and Team2_matches[4]>Team1_matches[4] ]): 
winner="Team 2" 
else:winner="it was a draw or something went wrong" 

它總是返回出於某種原因隊1由於我可憐的組合，請諮詢我如何能實現對於贏家的真正價值，而不必如果多條線路，如果這是正確的程序，我會做到這一點，就需要諮詢

如果沒有括號

if Team1_matches[0]>Team2_matches[0] and Team1_matches[1]>Team2_matches[1] and Team1_matches[2]>Team2_matches[2] and 
                                ^

信達xError：無效的語法

我得到的輸入是這樣的：

Team1_matches[0] = input("Enter the score that team 1 got on match 1? ") 

Answer 1

由於Rawing在評論中說，您對您的檢查和非空列表不需要括號被認爲是True。有關更多信息，請參閱the Python documentation。

試試這個：

Team1_matches=[1,2,3,4,5] 
Team2_matches=[5,5,5,5,6] 
if (Team1_matches[0]>Team2_matches[0] and Team1_matches[1]>Team2_matches[1] and Team1_matches[2]>Team2_matches[2] and Team1_matches[3]>Team2_matches[3] and Team1_matches[4]>Team2_matches[4]): 
    winner="Team 1" 
elif (Team2_matches[0]>Team1_matches[0] and Team2_matches[1]>Team1_matches[1] and Team2_matches[2]>Team1_matches[2] and Team2_matches[3]>Team1_matches[3] and Team2_matches[4]>Team1_matches[4]): 
    winner="Team 2" 
else: 
    winner="it was a draw or something went wrong" 

print(winner) 

>>> Team 2 

Answer 2

該解決方案使用內置all功能：

Team1_matches = [1,2,3,4,5] 
Team2_matches = [2,3,4,5,6] 

r = range(0, len(Team1_matches)) # range size 

if all(Team1_matches[i] > Team2_matches[i] for i in r): 
    winner="Team 1" 
elif all(Team2_matches[i] > Team1_matches[i] for i in r): 
    winner="Team 2" 
else: 
    winner="it was a draw or something went wrong" 

print(winner) # outputs: "Team 2"