可以說我擁有一個包含多個電子郵件和名稱哈希的數組。例如,我有這樣的事情:如何將.uniq與哈希用於唯一對?
foo = [{id: 1, name: 'Eric Cartman', email: '[email protected]'},
{id: 2, name: 'Eric Cartman', email: '[email protected]'},
{id: 3, name: "Cartman's mom", email: '[email protected]'},
{id: 4, name: 'Eric Cartman', email: '[email protected]'}]
如何使用.uniq
返回基於姓名和電子郵件的結合獨特的價值?例如,我想回到這樣的事情:
[{id: 1, name: 'Eric Cartman', email: '[email protected]'},
{id: 2, name: 'Eric Cartman', email: '[email protected]'},
{id: 3, name: "Cartman's mom", email: '[email protected]'}]
修復引號,順便說一句。現在它是無效的紅寶石代碼和一些人在這裏_will_對象:) –
你跟着@ Sergio的建議來修復報價,但你仍然有單引號和雙引號的混合。這冒犯了我的感情,所以我反對! –