如何告訴DataContractJsonSerializer不包含「__type」屬性

Question

我需要將KnownType添加到下面的代碼中，以便序列化成功。當我這樣做，將生成的JSON如下：

JSON form of Adult with 1 child: {"age":42,"name":"John","children":[{"__type":" 
Child:#TestJson","age":4,"name":"Jane","fingers":10}]} 

我怎麼有它不包括「__type」：「孩子：#TestJson」？我們在一些查詢中返回了數百個這些元素，並且額外的文本會加起來。

全碼：

using System; 
using System.Collections.Generic; 
using System.IO; 
using System.Runtime.Serialization; 
using System.Runtime.Serialization.Json; 

namespace TestJson 
{ 
    class Program 
    { 
     static void Main(string[] args) 
     { 
      Adult parent = new Adult {name = "John", age = 42}; 

      MemoryStream stream1 = new MemoryStream(); 
      DataContractJsonSerializer ser = new DataContractJsonSerializer(typeof(Adult)); 
      ser.WriteObject(stream1, parent); 

      stream1.Position = 0; 
      StreamReader sr = new StreamReader(stream1); 
      Console.Write("JSON form of Adult with no children: "); 
      Console.WriteLine(sr.ReadToEnd()); 


      Child child = new Child { name = "Jane", age = 4, fingers=10 }; 

      stream1 = new MemoryStream(); 
      ser = new DataContractJsonSerializer(typeof(Child)); 
      ser.WriteObject(stream1, child); 

      stream1.Position = 0; 
      sr = new StreamReader(stream1); 
      Console.Write("JSON form of Child with no parent: "); 
      Console.WriteLine(sr.ReadToEnd()); 


      // now connect the two 
      parent.children.Add(child); 

      stream1 = new MemoryStream(); 
      ser = new DataContractJsonSerializer(typeof(Adult)); 
      ser.WriteObject(stream1, parent); 

      stream1.Position = 0; 
      sr = new StreamReader(stream1); 
      Console.Write("JSON form of Adult with 1 child: "); 
      Console.WriteLine(sr.ReadToEnd()); 
     } 
    } 

    [DataContract] 
    [KnownType(typeof(Adult))] 
    [KnownType(typeof(Child))] 
    class Person 
    { 
     [DataMember] 
     internal string name; 

     [DataMember] 
     internal int age; 
    } 

    [DataContract] 
    class Adult : Person 
    { 
     [DataMember] 
     internal List<Person> children = new List<Person>(); 
    } 

    [DataContract] 
    class Child : Person 
    { 
     [DataMember] 
     internal int fingers; 
    } 
} 

Answer 1

正如我告訴你的最後一個問題，我不知道，但一些研究使我相信，以下可能實現你想要的：

var settings = new DataContractJsonSerializerSettings(); 
settings.EmitTypeInformation = EmitTypeInformation.Never; 

var serializer = new DataContractJsonSerializer(yourType, settings);