2013-06-12 82 views
0

我有喜歡的表/不喜歡的遊戲:idgame_idtype(喜歡/不喜歡),time如何通過此查詢進行訂購?

表例如:Image Link

此代碼通過給我的最後一個星期的遊戲有喜歡,爲了他們的喜歡數:

$limit = 10; 
$time = _time() - 60*60*24*7; 
$games_id = array(); 
$games_id_query = $this->db->execQuery("SELECT `game_id`, count(*) as `likes_count` FROM `likes` WHERE `type` = 'like' AND `time` > '{$time}' group by `game_id` order by `likes_count` DESC LIMIT {$limit}"); 
$games_id_num = $games_id_query->num_rows; 
if($games_id_num > 0) { 
    while($row = $games_id_query->fetch_object()) { 
     unset($row->likes_count); 
     $games_id[] = (array) $row; 
    } 
} 

我需要添加到此代碼。我想再買一個,這將是這個game_id,ASC的厭惡計數。

我該怎麼做?只有SQL ...非常感謝!

回答

0

你可能想是這樣的:

SELECT `game_id`, 
    SUM(IF(`type` = 'like', 1, 0)) AS likes_count, 
    SUM(IF(`type` = 'dislike', 1, 0)) AS dislikes_count 
FROM `likes` 
WHERE `time` > '{$time}' 
GROUP BY `game_id` 
ORDER BY `likes_count` DESC, `dislikes_count` ASC 
LIMIT {$limit} 

話雖這麼說,請考慮使用預處理語句和參數化查詢,而不是直接在SQL中嵌入你的PHP變量。

查看此問題以獲取更多信息:How can I prevent SQL injection in PHP?

-1

從DESC變爲ASC,是你想要的嗎?

SELECT game_id, count(*) as likes_count 
    FROM likes 
    WHERE type = 'like' 
    AND time > '{$time}' 
    group by game_id 
    order by likes_count ASC LIMIT {$limit}