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我正在使用以下代碼連接到一個虛擬主機服務器上的sql數據庫。 我對着錯誤PHP登錄數據庫連接錯誤
警告：mysqli的:: mysqli的（）（HY000/2002）：無法通過套接字 '/var/run/mysqld/mysqld.sock' 連接到本地MySQL服務器（ 2）在/srv/disk7/2067595/www/envoycc.atwebpages.com/DB_Connect.php第10行
第10行是$this->conn = new mysqli(DB_HOST, DB_USER, DB_PASSWORD, DB_DATABASE);
我的總代碼是
的config.php
<?php
/**
* Database config variables
*/
define("DB_HOST", "localhost");
define("DB_USER", "2067595_android");
define("DB_PASSWORD", "password");
define("DB_DATABASE", "2067595_android");
?>
DB_Connect.php
<?php
class DB_Connect {
private $conn;
// Connecting to database
public function connect() {
require_once 'config.php';
// Connecting to mysql database
$this->conn = new mysqli(DB_HOST, DB_USER, DB_PASSWORD, DB_DATABASE);
// return database handler
return $this->conn;
}
}
?>
DB_Functions.php
<?php
class DB_Functions {
private $conn;
// constructor
function __construct() {
require_once 'DB_Connect.php';
// connecting to database
$db = new Db_Connect();
$this->conn = $db->connect();
}
// destructor
function __destruct() {
}
/**
* Storing new user
* returns user details
*/
public function storeUser($name, $email, $password) {
$uuid = uniqid('', true);
$hash = $this->hashSSHA($password);
$encrypted_password = $hash["encrypted"]; // encrypted password
$salt = $hash["salt"]; // salt
$stmt = $this->conn->prepare("INSERT INTO users(unique_id, name, email, encrypted_password, salt, created_at) VALUES(?, ?, ?, ?, ?, NOW())");
$stmt->bind_param("sssss", $uuid, $name, $email, $encrypted_password, $salt);
$result = $stmt->execute();
$stmt->close();
// check for successful store
if ($result) {
$stmt = $this->conn->prepare("SELECT * FROM users WHERE email = ?");
$stmt->bind_param("s", $email);
$stmt->execute();
$user = $stmt->get_result()->fetch_assoc();
$stmt->close();
return $user;
} else {
return false;
}
}
/**
* Get user by email and password
*/
public function getUserByEmailAndPassword($email, $password) {
$stmt = $this->conn->prepare("SELECT * FROM users WHERE email = ?");
$stmt->bind_param("s", $email);
if ($stmt->execute()) {
$user = $stmt->get_result()->fetch_assoc();
$stmt->close();
return $user;
} else {
return NULL;
}
}
/**
* Check user is existed or not
*/
public function isUserExisted($email) {
$stmt = $this->conn->prepare("SELECT email from users WHERE email = ?");
$stmt->bind_param("s", $email);
$stmt->execute();
$stmt->store_result();
if ($stmt->num_rows > 0) {
// user existed
$stmt->close();
return true;
} else {
// user not existed
$stmt->close();
return false;
}
}
/**
* Encrypting password
* @param password
* returns salt and encrypted password
*/
public function hashSSHA($password) {
$salt = sha1(rand());
$salt = substr($salt, 0, 10);
$encrypted = base64_encode(sha1($password . $salt, true) . $salt);
$hash = array("salt" => $salt, "encrypted" => $encrypted);
return $hash;
}
/**
* Decrypting password
* @param salt, password
* returns hash string
*/
public function checkhashSSHA($salt, $password) {
$hash = base64_encode(sha1($password . $salt, true) . $salt);
return $hash;
}
}
?>
的login.php
<?php
require_once 'DB_Functions.php';
$db = new DB_Functions();
// json response array
$response = array("error" => FALSE);
if (isset($_POST['email']) && isset($_POST['password'])) {
// receiving the post params
$email = $_POST['email'];
$password = $_POST['password'];
// get the user by email and password
$user = $db->getUserByEmailAndPassword($email, $password);
if ($user != false) {
// use is found
$response["error"] = FALSE;
$response["uid"] = $user["unique_id"];
$response["user"]["name"] = $user["name"];
$response["user"]["email"] = $user["email"];
$response["user"]["created_at"] = $user["created_at"];
$response["user"]["updated_at"] = $user["updated_at"];
echo json_encode($response);
} else {
// user is not found with the credentials
$response["error"] = TRUE;
$response["error_msg"] = "Login credentials are wrong. Please try again!";
echo json_encode($response);
}
} else {
// required post params is missing
$response["error"] = TRUE;
$response["error_msg"] = "Required parameters email or password is missing!";
echo json_encode($response);
}
?>
當您將主機設置爲「localhost」時，MySQL會嘗試使用UNIX套接字文件連接到指定的主機，在您的情況下，它似乎不可用。將DB_HOST常量設置爲127.0.0.1應該是你的一天。 –
仍然有相同的錯誤。我有一個遠程虛擬主機服務器上的這個數據庫和PHP文件。我認爲localhost和127.0.0.1的意思是相同的東西127.0.0.1是由DNS生成的localhost的IP –
您需要發佈您用來查詢的代碼，因爲在測試中您發佈的內容不會產生任何錯誤。另外，看到您使用的是AwardSpace，您需要將'localhost'更改爲他們的服務器'???。awardspace.net'。他們可能不允許遠程連接免費託管，如果這是你註冊的。 –