Python列表按值賦值

我有一個列表撤消和另一個ap，我想保存每次我修改ap列表時複製撤消，但當我保存，例如在撤消[2]我已經做了ap ，Undo [1]與Undo [2]相同，它看起來像指定了列表ap而不是ap的值。我發現一個類似的問題，並試圖分配ap [：]，所以它會做一個副本，但它沒有。Python列表按值賦值

from Functionalitati import * 
from Ui import * 
from GlobalVr import * 
Active = True 
NumarApartamente = int(input("Numarul apartamentelor:")) 
cntA = 0 
while cntA < NumarApartamente: 
    ap.append({"gaz":{}, "apa":{}, "electricitate":{}, "canalizare":{}, "altele":{}}) 
    cntA = cntA + 1 
Undo = Undo + ap[ : ] 
while Active: 
    while True: 
     op1 = Umenu() 
     if op1 > 6 and op1 < 0: 
      print(x,'Nu este o comanda valida') 
     else: 
      break 
    if op1 == 0: 
     break 
    op2 = Submenu(op1) 

    if op1 == 6 and UndoCont > 0: 
     UndoCont = UndoCont - 1 
     Undo.pop() 
     ap = Undo[UndoCont] 
     print (Undo) 

    elif op1 == 1 and op2 == 1 : 
     ap = AddCheltuiala(ap) 
     Undo = Undo + ap[ : ] 
     UndoCont = UndoCont + 1 

    elif op1 == 1 and op2 == 2 : 
     ap = ModCheltuiala(ap) 
     Undo.append(ap[0:NumarApartamente - 1]) 
     UndoCont = UndoCont + 1 

    elif op1 == 2 and op2 == 1 : 
     ap = DelCheltuiala(ap) 
     Undo.append(ap[0:NumarApartamente - 1]) 
     UndoCont = UndoCont + 1 

    elif op1 == 2 and op2 == 2 :  
     ap = DelCCheltuiala(ap) 
     Undo.append(ap[0:NumarApartamente - 1]) 
     UndoCont = UndoCont + 1 

    elif op1 == 2 and op2 == 3 : 
     ap = DelTip(ap,NumarApartamente) 
     Undo.append(ap[0:NumarApartamente - 1]) 
     UndoCont = UndoCont + 1

我也試着用append和Undo = Undo + ap [：]，你可以看到。對不起，如果代碼有點混亂。編輯：我刪除了最後的編輯，我想更清楚所以我再拍一段代碼，以恢復我想說

from Functionalitati import * 
from Ui import * 
import datetime 
ap = [] #lista principala 

UndoCont = 0 
nrAp = int(input("Da-ti numarul apartamentelor:")) 
Undo = [None] * nrAp 
contor = 0 
while contor < nrAp: 
    ap.append({"gaz":{}, "apa":{}, "electricitate":{}, "canalizare":{}, "altele":{}}) 
    contor = contor + 1 

Undo[0] = ap[:] 
print(Undo) 
print("space" * 4) 
ap[1]["gaz"]["date"] = 100 
Undo[1] = ap[:] 
print (Undo)

輸出什麼：

Da-ti numarul apartamentelor:2 
[[{'gaz': {}, 'canalizare': {}, 'electricitate': {}, 'altele': {}, 'apa': {}}, {'gaz': {}, 'canalizare': {}, 'electricitate': {}, 'altele': {}, 'apa': {}}], None] 
spacespacespacespace 
[[{'gaz': {}, 'canalizare': {}, 'electricitate': {}, 'altele': {}, 'apa': {}}, {'gaz': {'date': 100}, 'canalizare': {}, 'electricitate': {}, 'altele': {}, 'apa': {}}], [{'gaz': {}, 'canalizare': {}, 'electricitate': {}, 'altele': {}, 'apa': {}}, {'gaz': {'date': 100}, 'canalizare': {}, 'electricitate': {}, 'altele': {}, 'apa': {}}]]

爲什麼撤銷[0]修改爲撤消[1]？我試着用Undo.append（list（ap））和Undo = Undo + list（ap）和ap [：]一樣，現在我試着初始化Undo和相同的結果。

來源

2016-11-21 user7006931

能否請你告訴你要如何'Undo'加入到照顧一個例子'ap'和現在看起來如何？ – elethan

好的我編輯了帖子 – user7006931

Solved.I真的不知道它是如何工作，但我使用copy.deepcopy()（copy.copy()沒有工作）

來源

2016-11-21 17:49:18 user7006931

Python列表按值賦值

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