陣列中元素的位置最大包含

Question

如何找到數組中最大值的位置，我知道最大值，但是我需要知道它的位置。

class maximumofarray 
{ 

    public static void main(String[] args) 
    { 
    double maximum; 
    int i; 
    double [] a={1.5,2.3,4.2,-9.4,2.0,12.9,-5.0,12.9,-0.1,-15.0,0.0}; 
    maximum=a[0]; 
    for (i = 1; i <= 10; i++) 
     { 
     if (a[i] > maximum) 
     { 
     maximum = a[i]; 
     } 

     } 
    System.out.println("The maximum element is "+maximum); 

    } 
} 

Answer 1

您需要按照下面的步驟：

（1）中聲明瞭一個多變量（maxLocation），這是需要收集的位置maximum

（2）當你正在分配最大（即，a[i] > maximum），也收集最大元件的位置作爲maxLocation

下面的代碼是下式給出：

double maximum; 
int i; 
int maxLocation =0; 
double [] a={1.5,2.3,4.2,-9.4,2.0,12.9,-5.0,12.9,-0.1,-15.0,0.0}; 
maximum=a[0]; 
for (i = 1; i <= 10; i++) 
    { 
    if (a[i] > maximum) 
    { 
     maximum = a[i]; //assign maximum value 
     maxLocation = i; //Also, collect the location as well to maxLocation 
    } 

    } 
System.out.println("The maximum element is "+maximum); 
System.out.println("The maximum element is "+maxLocation); 

} 

Answer 2

使用第二個變量...

double maximum; 
int locationOfMaximum; 
int i; 
double [] a={1.5,2.3,4.2,-9.4,2.0,12.9,-5.0,12.9,-0.1,-15.0,0.0}; 
maximum=a[0]; 
locationOfMaximum = 0; 
for (i = 1; i <= 10; i++) 
    { 
    if (a[i] > maximum) 
    { 
    maximum = a[i]; 
    locationOfMaximum = i; 
    } 

    } 
System.out.println("The maximum element is "+maximum+"; it appears at index "+locationOfMaximum); 

爲了記錄在案，有一些更多的變化，我建議，使代碼更易讀...

double [] a={1.5,2.3,4.2,-9.4,2.0,12.9,-5.0,12.9,-0.1,-15.0,0.0}; 

double maximum = Double.MIN_VALUE; // Or Double maximum = null; 
int locationOfMaximum = -1; 
for (int i = 0; i < a.length; i++) { 
    if (a[i] > maximum) { 
    maximum = a[i]; 
    locationOfMaximum = i; 
    } 

} 
System.out.println("The maximum element is "+maximum+"; it appears at index "+locationOfMaximum); 

Answer 3

您可以使用utilit方法Arrays.sort(a)對數組進行排序。那麼最大元素將停留在緯度指數。

double maximum; 
int i; 
double [] a={1.5,2.3,4.2,-9.4,2.0,12.9,-5.0,12.9,-0.1,-15.0,0.0}; 

Arrays.sort(a); 

System.out.println("The maximum element is "+a[a.length-1]);