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我看到了一個獲取接口的mac和ipv4地址的示例代碼。我改了一點試圖讓該接口,但該方案的IPv6地址失敗說「27:13:錯誤:分配給從類型類型‘u_int32_t’時,不兼容的類型「結構libnet_in6_addr」如何使用libnet獲取接口的ipv6地址?
#include <stdlib.h>
#include <libnet.h>
#include <stdint.h>
int main() {
libnet_t *l; /* libnet context */
char errbuf[LIBNET_ERRBUF_SIZE];
u_int32_t ip_addr;
struct libnet_ether_addr *mac_addr;
l = libnet_init(LIBNET_RAW4, NULL, errbuf);
if (l == NULL) {
fprintf(stderr, "libnet_init() failed: %s\n", errbuf);
exit(EXIT_FAILURE);
}
ip_addr = libnet_get_ipaddr4(l);
if (ip_addr != -1)
printf("IP address: %s\n", libnet_addr2name4(ip_addr,\
LIBNET_DONT_RESOLVE));
else
fprintf(stderr, "Couldn't get own IP address: %s\n",\
libnet_geterror(l));
u_int32_t ipv6_addr;
ipv6_addr = libnet_get_ipaddr6(l);
if (ip_addr != -1)
printf("IPv6 address: %s\n", libnet_addr2name6(ip_addr,\
LIBNET_DONT_RESOLVE));
else
fprintf(stderr, "Couldn't get own IPv6 address: %s\n",\
libnet_geterror(l));
mac_addr = libnet_get_hwaddr(l);
if (mac_addr != NULL)
printf("MAC address: %02X:%02X:%02X:%02X:%02X:%02X\n",\
mac_addr->ether_addr_octet[0],\
mac_addr->ether_addr_octet[1],\
mac_addr->ether_addr_octet[2],\
mac_addr->ether_addr_octet[3],\
mac_addr->ether_addr_octet[4],\
mac_addr->ether_addr_octet[5]);
else
fprintf(stderr, "Couldn't get own MAC address: %s\n",\
libnet_geterror(l));
libnet_destroy(l);
return 0;
}
我不不知道用什麼來存儲ipv6地址,所以我使用u_int32_t,我試過u_int64_t它不起作用。我想知道如果再次遇到這樣的基本問題,我應該在哪裏找到解決方案。我找不到有關ipv6地址的示例。