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Question

我在SAS一表，其中是例如CUSTOMER_ID 5列，他每月狀態中的最頻繁的值。客戶有6種不同的狀態。 例如

customer_id month1 month2 month3 month4 month5 
12345678  Waiting Inactive Active Active Canceled 

我想返回從MONTH1列的值 - month5這是最常見的。在這種情況下，它是「活動」值。 所以結果將是

customer_id frequent 
12345678  Active  

SAS中是否有任何功能？我有一些想法如何使用SQL做到這一點，但它會很複雜，有很多的情況下，條件等。我在SAS是新的，所以我想會有一些更好的解決方案。

Answer 1

如果您使用數組來分割數據集爲一個觀察一個客戶歷史，你可以在PROC SQL中使用匯總函數的每月輕鬆獲得最頻繁的發生，使用最近一個月（假設是每月5 ）打破關係。

data want1; 
    set have; 
    array m(*) month1 -- month5; 
    do i = 1 to dim(m); 
     cid = customer_id; 
     frequent = m(i); 
     position = i; 
     output; 
    end; 
    keep cid frequent position; 
run; 

proc sql; 
    create table want2 as select 
    cid as customer_id, 
    frequent, 
    max(position) as max_pos, 
    count(frequent) as count 
    from want1 
    group by cid, frequent; 
quit; 

proc sort data = want2; by customer_id descending count descending max_pos; run; 

data want3; 
    set want2; 
    by customer_id descending count descending max_pos; 
    if first.customer_id; 
    drop max_pos count; 
run; 

Answer 2

解決方案稍差，但它確實爲兩種不同價值觀的工作，在這種情況下5個月。如果主動> = 3號，這是最常見的值：

select customer_id, case when (case when month1 = 'Active' then 1 else 0 end + 
           case when month2 = 'Active' then 1 else 0 end + 
           case when month3 = 'Active' then 1 else 0 end + 
           case when month4 = 'Active' then 1 else 0 end + 
           case when month5 = 'Active' then 1 else 0 end) >= 3 
          then 'Active' else 'Waiting' end 
from tablename 

的另一種方式，UNION ALL：

select customer_id, month, count(*) as cnt 
(
    select customer_id, month1 as month from tablename 
    UNION ALL 
    select customer_id, month2 from tablename 
    UNION ALL 
    select customer_id, month3 from tablename 
    UNION ALL 
    select customer_id, month4 from tablename 
    UNION ALL 
    select customer_id, month5 from tablename 
) 
group by customer_id, month 
order by cnt 
fetch first 1 row only 

哪裏FETCH FIRST是ANSI SQL，可能是某些DBMS產品TOP或LIMIT。