我一直在自學下了幾個月,當我有時間,我遇到了一個問題,我不知道如何解決。衝突的類型和x的先前的聲明在這裏......什麼?
具體而言,當我嘗試編譯這個使用gcc,我得到:
geometry.c:8: error: conflicting types for ‘trapezoid’ geometry.c:7: note: previous declaration of ‘trapezoid’ was here geometry.c:48: error: conflicting types for ‘trapezoid’ geometry.c:7: note: previous declaration of ‘trapezoid’ was here geometry.c:119: error: conflicting types for ‘trapezoid_area’ geometry.c:59: note: previous implicit declaration of ‘trapezoid_area’ was here geometry.c: In function ‘cone_volume’: geometry.c:128: error: called object ‘3.14100000000000001421085471520200371742248535156e+0’ is not a function geometry.c: In function ‘cylinder_volume’: geometry.c:136: error: called object ‘3.14100000000000001421085471520200371742248535156e+0’ is not a function
現在,我想我可能需要強制轉換的功能,但同樣,我不知道。
它看起來要讀取PI,我已經定義爲3.141,爲函數。有沒有一種方法可以避免使用幻數3.141(儘管它比其他幻數小得多)?
//Geometric formulae
#include <stdio.h>
#include <math.h>
#define PI 3.141
float trapezoid(float b1, float b2, float h);
int trapezoid();
float sphere_volume(float r);
int sphere();
float cone_volume(float r, float h);
int cone();
float pyramid_volume(float b, float h);
int pyramid();
float cylinder_volume(float r, float h);
int cylinder();
int main(void) {
char selection = 0;
while(selection != 'q') {
printf("\t--Geometric Formulas--\n");
printf("\tSelection an option from the menu: ");
scanf("%c", & selection);
switch(selection) {
case 1: //Trapezoid area
printf("%d", trapezoid());
break;
case 2: //Sphere volume
printf("%d", sphere());
break;
case 3: //Cone volume
printf("%d", cone());
break;
case 4: //Pyramid volume
printf("%d", pyramid());
break;
case 5: //Cylinder volume
printf("%d", cylinder());
break;
default:
break;
}
}
}
// --Shape Menus--
//Trapezoid
int trapezoid() {
float h = 0, b1 = 0, b2 = 0;
float traparea;
printf("\tTrapezoid base 1: ");
scanf("%3f", &b1);
printf("\tTrapezoid base 2: ");
scanf("%3f", &b2);
printf("\tTrapezoid height: ");
scanf("%3f", &b2);
traparea = trapezoid_area(b1, b2, h);
printf("\tTrapezoid Area: %3f\n", traparea); }
//Sphere
int sphere() {
float r = 0;
float spherevol;
printf("\tSphere radius: ");
scanf("%f", &r);
spherevol = sphere_volume(r);
printf("\tSphere volume: %3f\n", spherevol); }
//Cone
int cone() {
float r = 0, h = 0;
float conevol;
printf("\tCone radius: ");
scanf("%f", &r);
printf("\tCone height: ");
scanf("%f", &h);
conevol = cone_volume(r, h);
printf("\tCone volume: %3f\n", conevol); }
//Pyramid
int pyramid() {
float b = 0, h = 0;
float pyramidvol;
printf("\tPyramid base: ");
scanf("%f", &b);
printf("\tPyramid height: ");
scanf("%f", &h);
pyramidvol = pyramid_volume(b, h);
printf("\tPyramid volume: %3f\n", pyramidvol); }
//Cylinder
int cylinder() {
float r = 0, h = 0;
float cylindervol;
printf("\tCylinder radius: ");
scanf("%f", &r);
printf("\tCylinder height: ");
scanf("%f", &h);
cylindervol = cylinder_volume(r, h);
printf("Cylinder volume: %3f", cylindervol); }
// --Geometric Formulas--
//Trapezoid Area Computation
float trapezoid_area(float b1, float b2, float h) {
return ((b1 + b2) * h)/2; }
//Sphere Volume Computation
float sphere_volume(float r) {
return ((pow(r,3)) * (4 * PI))/3; }
//Cone Volume Computatioin
float cone_volume(float r, float h) {
return ((PI(pow(r,2)) * h))/3; }
//Pyramid Volume Computation
float pyramid_volume(float b, float h) {
return (b * h)/3; }
//Cylinder Volume Computation
float cylinder_volume(float r, float h) {
return (PI(pow(r,2))) * h; }
我不介意提名,但是......我只回答了問題的一小部分。你確定你打算選擇我的正確答案嗎? – 2011-04-04 23:43:48