我wrote a function這個前一陣子。
to_wateryear <- function(thedate){
thedate = as.Date(thedate)
year = as.integer(substr(thedate, 1, 4))
cutoff = cutoff = as.Date(paste(year, '-10-01', sep=''))
return(ifelse(thedate < cutoff,
year*1000 + thedate - as.Date(paste(year - 1, '-09-30', sep='')),
(year + 1)*1000 + thedate - as.Date(paste(year, '-09-30', sep=''))))
}
例子:
to_wateryear(as.Date(Sys.time()))
to_wateryear('2013-10-01')
# leap year behavior
to_wateryear('2012-09-30')
to_wateryear('2013-09-30')
to_wateryear('2012-02-29')
to_wateryear('2013-03-31')
編輯從您的意見,它聽起來就像你真正想要的是分裂您rasterbrick水年,而不是在水文一年方面表示日期。
library(raster)
nl <- 768
s <- brick(nrows = 510, ncols = 1068,
xmn = -180, xmx = 180, ymn = -90, ymx = 90,
crs = "+proj=longlat +datum=WGS84",
nl = nl,values=TRUE)
dates <- seq(as.Date("1950-01-01"), as.Date("2013-12-31"), by = "month")
# use water year
s <- setZ(s, to_wateryear(dates))
vals <- 1:ncell(s)
s[]=vals
# split by water year
hyears = unique(getZ(s) %/% 1000)
res = vector("list", length(hyears))
for(i in 1:length(hyears))
res[[i]] = s[[which(getZ(s) %/% 1000 == hyears[i])]]
names(res) = paste0("HY", hyears)
這可能是非常有幫助的。你可以在我的'rasterbrick,s'上測試它嗎? – code123
我的確提供了上面的示例數據。當我到達我的電腦時,我會嘗試它。但是,請嘗試讓我知道它是否適用於您。謝謝。 – code123
我嘗試了以下,但得到的數字,而不是日期:'s < - setZ(s,to_wateryear(日期))' – code123