要多坯料在變量（未捕獲的SyntaxError：意外令牌非法的）

Question

alert(name); 

輸出應該「pikkertonnode_1334187978」

的第二'是遠離文本的末尾。

這是我的代碼：

var name; 
var namehelp; 
// For individually tab 
function refresher() { 

    var url = 'output.php?string=' + choice[0].innerText; 
    var split = url.split("[new]"); 
    var series = "[" ; 
    for (var i = 1; i < split.length; i++) 
    { 
      namehelp = split[i]; 
      var splithelp = namehelp.split(")"); 
      namehelp = splithelp[1];   
      alert(namehelp); 
      name = "'" + namehelp + "'"; 
      alert(name); 
      series = series + "{ name : " + name + " , data : data[" + (i-1) + "] }," ; 
    } 

VAR URL是這樣的：

http://172.23.133.61:60080/pages/select-multiple-start/output.php?string=[new]frequency%20(Monitor%201)pikkertonnode_1334156507[new]loadvalue%20(Monitor%201)pikkertonnode_1334156507 

Answer 1

可能是你的變量包含不必要spaces.Use以下以刪除空格

alert(name.replace(/\s/g, ""));