.value返回Nothing（javaScript）

Question

我想從聯繫人中獲取電話號碼的值，但我要麼將[object，Object]返回給我，要麼什麼也沒有。當我嘗試匹配[我] .phoneNumbers我得到[對象，對象]，當我添加匹配[i] .phoneNumbers [0] .value，我的警報完全停止。

function callme() { 
    var options = new ContactFindOptions(); 
    options.filter = ""; //leaving this empty will find return all contacts 
    options.multiple = true; //return multiple results 
    console.log(options); 
    var filter = ["displayName", "phoneNumbers"]; //an array of fields to compare against the options.filter 

    navigator.contacts.find(filter, successFunc, errFunc, options); 

    function successFunc(matches) { 
     for (var i = 0; i < matches.length; i++) { 
      //this loops through all of the contacts 

      var contact_name = matches[i].displayName; 
      var contact_number = matches[i].phoneNumbers; //this returns [object, Object] 
      // var contact_number = matches[i].phoneNumbers[0].value; returns nothing at all 
      var contact_full = contact_name + " " + contact_number; 
     } 
     alert(contact_full); 
    } 

    function errFunc() { 
     alert("oh no!"); 
    } 
}; 

Answer 1

我不知道你的JSON對象的結構是，但你可以在Firebug，如果你不知道該怎麼做調試，那麼就嘗試下以下幾點：

function successFunc(matches) { 
     for (var i = 0; i < matches.length; i++) { 
      //this loops through all of the contacts 

     var contact_name = matches[i].displayName; 
     alert(JSON.stringify(matches[i].phoneNumbers); 
var contact_number = matches[i].phoneNumbers; //this returns [object, Object] 
      // var contact_number = matches[i].phoneNumbers[0].value; returns nothing at all 
      var contact_full = contact_name + " " + contact_number; 

    } 
    alert(contact_full); 
} 

警報對話框出現後，您將能夠看到對象的屬性列表。