最小值最大值與標識 - 甲骨文

Question

試圖讓這個輸出Oracle 8i中：

column1 |time 
________|_______ 
    ABC | 00:00:01 
    END | 00:00:03 
    123 | 00:00:04 
    END | 00:00:07 
    ABC | 00:00:08 
    END | 00:00:10 

與來自另一個查詢

column1 |time  |ID 
    ________|___________| 
     ABC | 00:00:01 | 1 
     ABC | 00:00:02 | 1 
     ABC | 00:00:03 | 1 
     123 | 00:00:04 | 1 
     123 | 00:00:05 | 1 
     123 | 00:00:06 | 1 
     123 | 00:00:07 | 1 
     ABC | 00:00:08 | 2 
     ABC | 00:00:09 | 2 
     ABC | 00:00:10 | 2 

此查詢獲取的最小值和最大值，而不考慮ID此輸出。

select (case when n.n = 1 then column1 else 'END' end) as column1, 
     (case when n.n = 1 then firsttime else lasttime end) as "time" 
from (select column1, min(time) as firsttime, max(time) as lasttime 
     from t 
     group by column1 
    ) t cross join 
    (select 1 as n from dual union all select 2 from dual) n 
order by column1, n.n; 

如何做同樣的事情，而不是獲得第一列和第一列的出現值，考慮ID以及？

Answer 1

您需要包括在邏輯id，無論是在group by並在order by：

select (case when n.n = 1 then column1 else 'END' end) as column1, 
     (case when n.n = 1 then firsttime else lasttime end) as "time" 
from (select column1, id, min(time) as firsttime, max(time) as lasttime 
     from t 
     group by column1, id 
    ) t cross join 
    (select 1 as n from dual union all select 2 from dual) n 
order by id, column1, n.n;