我一直在環顧四周的論壇,並嘗試了一切,但我不能讓我的按鈕禁用後點擊它,我剛開始使用PHP,這是我的第一個項目之一。它是一個喜歡和不喜歡的系統。有人知道這個遊戲機嗎? 當您按下類似按鈕或不喜歡按鈕時,我希望禁用這兩個按鈕。1單擊然後禁用 - PHP
<!--Like System-->
<center>
<?php
$sql = "SELECT * FROM likes";
$result = mysqli_query($con, $sql);
if (mysqli_num_rows($result) > 0) {
// output data of each row
while($row = mysqli_fetch_assoc($result)) {
?> <h1 class="lcount"><?php echo $row["average"];?> <span class="glyphicon glyphicon-signal"></span></h1></br><?php
}
} else {
echo "0 results";
}
?>
<?php
$sql = "SELECT * FROM likes";
$result = mysqli_query($con, $sql);
if (mysqli_num_rows($result) > 0) {
// output data of each row
while($row = mysqli_fetch_assoc($result)) {
?> <h1 class="lcount"><?php echo $row["like"];?>
<span style="color: green;"class="glyphicon glyphicon-thumbs-up"></span></h1></br>
<?php
}
} else {
echo "0 results";
}
?>
<?php
$sql = "SELECT * FROM likes";
$result = mysqli_query($con, $sql);
if (mysqli_num_rows($result) > 0) {
// output data of each row
while($row = mysqli_fetch_assoc($result)) {
?> <h1 class="lcount"><?php echo $row["dislike"];?>
<span style="color: red;" class="glyphicon glyphicon-thumbs-down"></span></h1>
<?php
}
} else {
echo "0 results";
}
?>
<?php
if(isset($_POST['like'])){
$sql = "UPDATE `likes` SET `like` = `like` + 1 , `average` = `average` + 1";
if (mysqli_query($con, $sql)) {
} else {
echo "Error updating record: " . mysqli_error($con);
}
}
?>
<?php
if(isset($_POST['dislike'])){
$sql = "UPDATE `likes` SET `dislike` = `dislike` + 1 , `average` = `average` - 1";
if (mysqli_query($con, $sql)) {
} else {
echo "Error updating record: " . mysqli_error($con);
}
}
?>
<form type="#" method="post">
<button name="like" type="submit" class="btn btn-success">
<span class="glyphicon glyphicon-thumbs-up"></span></button>
<button name="dislike" type="submit" class="btn btn-danger">
<span class="glyphicon glyphicon-thumbs-down"></span></button>
</form>
</center>
<!--Like System END-->
我覺得像JavaScript將這個 – Maciej
着它只有PHP的工作更適合? – FluffyMe
PHP需要您重新加載頁面,因爲代碼在服務器上執行。 Javascript在瀏覽器中執行,因此它更適合操作UI,例如禁用按鈕。理論上,你可以在PHP中做到這一點,但它可能會非常混亂,總體上不值得。 – Maciej