LUA編程，ESP8266 NODEMCU串行通信

我想通過串行端口的ESP8266 12E NODE MCU開發套件發送數據到一個arduino串行端口。LUA編程，ESP8266 NODEMCU串行通信

我已經很難找到使用的語法的一個例子，我嘗試使用serial.print（）通過arduino發送數據，它的工作原理，但我不確定如何在Lua中完成此操作。

任何幫助表示讚賞

我能得到的SSID和密碼形式的Arduino

INIT.lua

SSID = "XXXX" 
Password = "XXXX" 
wifi.setmode(wifi.STATION) 
wifi.sta.config(SSID,Password) -- Replace with your AP Name and security key. 
wifi.sta.connect() 
tmr.alarm(1, 1000, 1, function() 
if wifi.sta.getip()== nil then 
print("Obtaining IP...") 
else 
tmr.stop(1) 
print("Got IP. "..wifi.sta.getip()) 
dofile("LED_on_off.lua") 

end 

end)

LED_ON_OFF LUA

print(wifi.sta.getip()) 

led2 = 4 
gpio.mode(led1, gpio.OUTPUT) 
gpio.mode(led2, gpio.OUTPUT) 
srv=net.createServer(net.TCP) 
srv:listen(80,function(conn) 
    conn:on("receive", function(client,request) 
     local buf = ""; 
     local _, _, method, path, vars = string.find(request, "([A-Z]+) (.+)?(.+) HTTP"); 
     if(method == nil)then 
      _, _, method, path = string.find(request, "([A-Z]+) (.+) HTTP"); 
     end 
     local _GET = {} 
     if (vars ~= nil)then 
      for k, v in string.gmatch(vars, "(%w+)=(%w+)&*") do 
       _GET[k] = v 
      end 
     end 
     buf = buf.."<h1> ESP8266 Web Server</h1>"; 

     buf = buf.."<p>GPIO2 <a href=\"?pin=ON2\"><button>ON</button></a>&nbsp;<a href=\"?pin=OFF2\"><button>OFF</button></a></p>"; 
     local _on,_off = "","" 
     if(_GET.pin == "OFF2")then 
       gpio.write(led2, gpio.HIGH); 
     elseif(_GET.pin == "ON2")then 

**********Here i would like to send data ot arduini that pin is swithced oN ************ 

       gpio.write(led2, gpio.LOW); 
     end 
     client:send(buf); 
     client:close(); 
     collectgarbage(); 
    end) 
end)

來源

2016-10-10 Vinay Harne