Pygame創建一個新的屏幕

Question

基本上我一直堅持幾個小時試圖創建一個空白模板，當用戶點擊新遊戲。我告訴代碼然後取消while循環並使用Background.fill（）函數創建一個空白屏幕，但它不起作用。這是我的代碼。

import pygame 
import random 
import sys 
from pygame import * 

def text(): 
    font = pygame.font.SysFont("monospace", 40) 
    surfacefont = font.render("Tower Defense", True, black) 
    surfaceR = surfacefont.get_rect() 
    surfaceR.center = (400,50) 
    Background.blit(surfacefont, surfaceR) 

    text = font.render("Start game", True, black) 
    textpos = surfacefont.get_rect() 
    textpos.center = (425,200) 
    Background.blit(text, textpos) 

    text = font.render("Exit Game", True, black) 
    textpos = surfacefont.get_rect() 
    textpos.center = (435,260) 
    Background.blit(surfacefont, surfaceR) 
    Background.blit(text, textpos) 
    pygame.display.update() 

def button(): 
    click = pygame.mouse.get_pressed() 
    pos = pygame.mouse.get_pos() 
    if 285+205 > pos[0] > 285 and 175+50 > pos[1] > 175: 
     pygame.draw.rect(Background, (100,100,100),(263,175,250,50)) 
     if click[0] == 1: 
      cancelLoop() 
    else: 
     pygame.draw.rect(Background, white,(285,175,205,50)) 

    if 278+220 > pos[0] > 278 and 234+50 > pos[1] > 234: 
     pygame.draw.rect(Background, (100,100,100),(278,234,220,50)) 
     if click[0] == 1: 
      pygame.quit() 
      sys.exit() 
    else: 
     pygame.draw.rect(Background, white,(278,234,220,50)) 

def cancelLoop(): 
    global intro 
    intro = 0 
    runGame() 

def runGame(): 
    Background.fill(red) 

pygame.init() 

display_width = 800 
display_height = 600 

black = (0,0,0) 
white = (255,255,255) 
red = (255,0,0) 
Background = pygame.display.set_mode((display_width,display_height)) 
pygame.display.set_caption("Tower Defense") 
intro = 1 
while intro == 1: 
    Background.fill(white) 
    button() 
    text() 
    for event in pygame.event.get(): 
     if event.type == quit: 
      pygame.quit() 
      sys.exit() 
    pygame.display.update() 
    pygame.display.flip() 

Answer 1

的問題是，你得到有效的退出你的遊戲，當你調用intro == 0，因爲您取消while循環。因此，該程序將在介紹之後結束。您可以製作一個主循環，其中也可以調用runGame()函數，也可以爲您的介紹和實際遊戲製作單獨的循環，而不是僅爲您的介紹製作一個while循環。 這將是我將如何親自寫它：

import pygame 
import random 
import sys 
from pygame import * 

pygame.init() 

display_width = 800 
display_height = 600 

black = (0,0,0) 
white = (255,255,255) 
red = (255,0,0) 
Background = pygame.display.set_mode((display_width,display_height)) 
pygame.display.set_caption("Tower Defense") 

def text(): 
    font = pygame.font.SysFont("monospace", 40) 
    surfacefont = font.render("Tower Defense", True, black) 
    surfaceR = surfacefont.get_rect() 
    surfaceR.center = (400,50) 
    Background.blit(surfacefont, surfaceR) 

    text = font.render("Start game", True, black) 
    textpos = surfacefont.get_rect() 
    textpos.center = (425,200) 
    Background.blit(text, textpos) 

    text = font.render("Exit Game", True, black) 
    textpos = surfacefont.get_rect() 
    textpos.center = (435,260) 
    Background.blit(surfacefont, surfaceR) 
    Background.blit(text, textpos) 
    pygame.display.update() 

def button(): 
    click = pygame.mouse.get_pressed() 
    pos = pygame.mouse.get_pos() 
    if 285+205 > pos[0] > 285 and 175+50 > pos[1] > 175: 
     pygame.draw.rect(Background, (100,100,100),(263,175,250,50)) 
     if click[0] == 1: 
      runGame() 
    else: 
     pygame.draw.rect(Background, white,(285,175,205,50)) 

    if 278+220 > pos[0] > 278 and 234+50 > pos[1] > 234: 
     pygame.draw.rect(Background, (100,100,100),(278,234,220,50)) 
     if click[0] == 1: 
      pygame.quit() 
      sys.exit() 
    else: 
     pygame.draw.rect(Background, white,(278,234,220,50)) 

def runGame(): 
    Background.fill(red) 

intro = 1 
while intro == 1: 
    Background.fill(white) 
    button() 
    text() 
    for event in pygame.event.get(): 
     if event.type == quit: 
      pygame.quit() 
      sys.exit() 
    pygame.display.update() 
    pygame.display.flip()