2017-01-04 69 views
1

我在Payara服務器上設置了一個Java EE端點,我嘗試使用Autobahn WebSockets連接Android客戶端。我有以下設置:「Connection refused」Autobahn Android to Java EE Endpoint

我的WebSocket端點服務器上:

public class CommunicationSocket extends Endpoint { 

    @Override 
    public void onOpen(Session aSession, EndpointConfig aConfig) { 
     aSession.addMessageHandler(new MessageHandler.Whole<byte[]>() { 
     @Override 
     public void onMessage(byte[] aMessage) { 
      // Do something fun 
     } 
     }); 
    } 
} 

我註冊的WebSocket這樣:

public class RegisterSocket implements ServerApplicationConfig { 

    @Override 
    public Set<ServerEndpointConfig> getEndpointConfigs(
      Set<Class<? extends Endpoint>> aEndpointClasses) { 
     Set<ServerEndpointConfig> result = new HashSet<>(); 
     for (Class endpointClass : aEndpointClasses) { 
      if (endpointClass.equals(CommunicationSocket.class)) { 
      ServerEndpointConfig sec 
         = ServerEndpointConfig.Builder.create(endpointClass, 
          "/WebSocket").build(); 
      result.add(sec); 
      } 
     } 
     return result; 
    } 

    @Override 
    public Set<Class<?>> getAnnotatedEndpointClasses(
      Set<Class<?>> aScanned) { 
     return Collections.emptySet(); 
    } 

} 

WebSocket的,現在可以達到ATT WS://本地主機:46588 /服務器/ WebSocket的。我已經證實,它具有以下JavaScript的工作中鉻:

function WebSocketTest() { 
    if ("WebSocket" in window) { 
     ws = new WebSocket("ws://localhost:46588/Server/WebSocket"); 

     ws.onopen = function() { 
     ws.send("Message to send"); 
      alert("Message is sent..."); 
     }; 

     ws.onmessage = function (evt) { 
       var received_msg = evt.data; 
       alert("Message is received... \n" + received_msg); 
     }; 

    } else { 
     // The browser doesn't support WebSocket 
     alert("WebSocket NOT supported by your Browser!"); 
    } 
} 

然而,當我嘗試使用我的Android客戶端使用的高速公路連接,插座關閉,不能夠建立與消息的連接「連接被拒絕」。我用下面的代碼中的onCreate連接(mSocket是活動類的字段):

WebSocketHandler messageHandler = new WebSocketHandler() { 
    @Override 
    public void onOpen() { 
     System.out.println("Connected..."); 
    } 

    @Override 
    public void onClose(int code, String reason) { 
     System.out.println("Socket closing: " + reason); 
     mSocket = null; 
    } 

    @Override 
    public void onTextMessage(String payload) { 
     System.out.println("Received: " + payload); 
    } 

    @Override 
    public void onBinaryMessage(byte[] payload) { 
     System.out.println("Message received: " + payload);   
    } 
}; 

mSocket = new WebSocketConnection(); 
try { 
    String address = "ws://localhost:46588/Server/WebSocket"; 
    mSocket.connect(address, messageHandler); 
} catch (WebSocketException e) { 
    System.out.println("Could not connect to WebSocket: " 
      + e.getMessage()); 
    mSocket = null; 
} 

我有互聯網的權限我在我的表現爲這樣:

<uses-permission android:name="android.permission.INTERNET"> 
</uses-permission> 

有沒有在我的代碼什麼或方法是錯誤的?是否有可能記錄/捕獲連接事件(握手或不能)以揭示連接被拒絕的原因?

回答

0

而我準備發佈問題,我最後一次搜索了一個:lo and behold,本地主機不是運行模擬器的機器的本地主機(我猜它是仿真設備的本地主機)。因此,使用:

10.0.2.2:[port] 

代替

localhost:[port] 

,這將是在模擬器上細(不要忘了,如果在實際設備上運行的改變)