發送電子郵件給每個符合條件的用戶

Question

由於評論中的以下建議，我更新了我的代碼。現在的問題是我得到一個錯誤。下面是新的代碼：

<?php 
require_once "config.php"; 
$idspam = "1"; 
$sql = "SELECT * FROM company WHERE ID = '$idspam'"; 
$result = mysql_query($sql); 
while ($row = mysql_fetch_array($result)) 
{ 
    $companyname = $row['CompanyName']; 
} 
$sql = "SELECT * FROM users"; 
$result = mysql_query($sql); 
$rows = mysql_fetch_array($result); 
foreach($rows as $row) 
{ 
    $Agent = $row['username']; 
    $fullname = $row['fullname']; 
    $phone = $row['phone']; 
    $Agentmail = $row['mail']; 
    $checkstat = "New customer"; 
    $result = mysql_query("SELECT * FROM data WHERE Status = '$checkstat' AND Agent = '$Agent'"); 
    $rows = mysql_fetch_array($result); 
    foreach($rows as $row) 
     { 
     $LastName = $row['LastName']; 
     if (empty($row['ProductPriceUSD'])) { 
      $ProductPriceEUR = $row['ProductPriceEUR']; 
      $symbol = "&#8364;"; 
      $Productprice = ($ProductPriceEUR . $symbol); 
     } 
     if (empty($row['ProductPriceEUR'])) { 
      $ProductPriceUSD = $row['ProductPriceUSD']; 
      $symbol = "$"; 
      $Productprice = ($symbol . $ProductPriceUSD); 
     } 
     $CustomerPriceRAW = $row['CustomerPrice']; 
     $eur = "&#8364;"; 
     $email = $row['Email']; 
     $a = mt_rand(100000,999999); 
     $MD5Pass = md5($LastName . $a); 
     $type = "Initial"; 
     $sql = "SELECT * FROM emails WHERE AddedBy = '$Agent' ORDER BY RAND() LIMIT 1"; 
     $result = mysql_query($sql); 
     while ($row = mysql_fetch_array($result)) 
     { 
      $content = $row['Content']; 
      $subject = $row['Subject']; 
     } 
     $Newstatus = "Contacted"; 
     $Newline = "<br>"; 
     $replaceWord = array(

     "[name]" => $row['FirstName'], 
     "[lastname]" => $row['LastName'], 
     "[product]" => $row['ProductName'], 
     "[username]" => $row['CustomerUser'], 
     "[agent]" => $row['Agent'], 
     "[productssold]" => $row['ProductsSold'], 
     "[customerprice]" => ($CustomerPriceRAW . $eur), 
     "[password]" => ($LastName . $a), 
     "[productprice]" => $Productprice, 
     "[newline]" => $Newline, 
     ); 
     ob_start(); 
     include("./email/mailtemplate.php"); 
     $sendmsg = ob_get_clean(); 
     $message = $sendmsg; 
     $body = strtr($content, $replaceWord); 
     $headers = "From:".$companyname." ".$Agentmail."\r\n"; 
     $headers .= "MIME-Version: 1.0\r\n"; 
     $headers .= "Content-Type: text/html; charset=ISO-8859-1\r\n"; 
     $contactdate = date("Y-m-d"); 
     $sevendays = date('Y-m-d', strtotime("+7 days")); 
     $todo = "Followup"; 
     mysql_query("UPDATE data SET CustomerPass = '$MD5Pass', Status = '$Newstatus', Contacted = '$contactdate', SevenDays = '$sevendays', ToDo = '$todo'"); 
     mail($email, $subject, $body, $headers); 
    } 
} 

?> 

，這裏是錯誤，我得到

Warning: Invalid argument supplied for foreach() in /home/user/public_html/cronmailinitial.php on line 22 

爲什麼？我想挑選我的所有員工（第一次），並聯系他們的每個客戶。因此，一個例子是： 對於代理「約翰」 截齒，「約翰」 增加對他們每個人的所有客戶選擇不同的電子郵件模板 發送

這就是它的假設也是閒着。在此先感謝

Answer 1

兩件事情：

1. 這個API已被棄用

2. 改變所有

   而（$行= mysql_fetch_array（$結果））

到更像

$rows = mysql_fetch_array($result); 
foreach($rows as $row) 
{ 
    .. do something with $row.... 
}