我有兩個頁面,一個發送的file_get_contents請求:獲取IP從的file_get_contents請求
$postdata = http_build_query(array('install' => 'true', 'url' => $_SERVER['SERVER_NAME'], 'key' => 'XXXXXXXXXXXX'));
$opts = array('http' =>
array(
'method' => 'POST',
'header' => 'Content-type: application/x-www-form-urlencoded',
'content' => $postdata
)
);
$context = stream_context_create($opts);
$registration_key = file_get_contents('http://example.com/register.php', false, $context);
和頁面接收呼叫(http://example.com/register.php)和我試圖抓住請求來自何處的IP無濟於事。我曾嘗試:
$_SERVER['HTTP_CLIENT_IP']
$_SERVER['HTTP_VIA']
$_SERVER['HTTP_X_FORWARDED_FOR']
$_SERVER['REMOTE_ADDR']
(IP,但計算機發送或接收的請求不是一個IP)
任何想法,我可以在發送請求的計算機上找到更多信息?
在此先感謝!
如果你已經使用'_context_create'你可以只增加了' '頭'=>'和'「\ NX-轉發,爲:$ _SERVER [REMOTE_ADDR]「',這樣你就可以像register $ _SERVER ['HTTP_X_FORWARDED_FOR']'那樣在register.php腳本中接收它。 – mario 2011-04-15 22:59:52