Mysql查詢內部連接？

-1

這個查詢有什麼問題？它說：使用附近的語法'INNER JOINcm_competitions ON cm_matches.competition_id = cm_competitions.compet 這是怎麼回事？Mysql查詢內部連接？

$query_matches = "SELECT cm_matches.match_id, cm_competitions.name 
        INNER JOIN cm_competitions.name 
        ON cm_matches.competition_id = cm_competitions.competition_id 
        FROM cm_matches 
        WHERE cm_matches.club_h_id = 8 
        OR cm_matches.club_v_id = 8";

來源

2013-07-23 Rrezarta Muja

基本的順序 - 'SELECT col FROM tbl1 INNER JOIN tbl2 ON tbl1.col = tbl2.col'而不是'SELECT col INNER JOIN ...' –

您INNER JOIN這應該是INNER JOIN後前放置FROM cm_matches。因此，嘗試此查詢：

SELECT cm_matches.match_id, cm_competitions.name 
    FROM cm_matches 
INNER JOIN cm_competitions 
    ON cm_matches.competition_id = cm_competitions.competition_id 
WHERE cm_matches.club_h_id = 8 
    OR cm_matches.club_v_id = 8

來源

2013-07-23 08:25:42 hims056

使用INNER 後JOIN FROM標籤：

$query_matches = "SELECT cm_matches.match_id, cm_competitions.name 
        FROM cm_matches 
        INNER JOIN cm_competitions 
        ON cm_matches.competition_id = cm_competitions.competition_id 
        WHERE cm_matches.club_h_id = 8 
        OR cm_matches.club_v_id = 8";

來源

2013-07-23 08:25:55 Bora

謝謝你的照亮我！ –

-1

嘗試：

$query_matches = "SELECT cm_matches.match_id, cm_competitions.name FROM cm_matches INNER JOIN cm_competitions ON cm_matches.competition_id = cm_competitions.competition_id WHERE cm_matches.club_h_id = 8 OR cm_matches.club_v_id = 8";

來源

2013-07-23 08:26:52

沒有解釋 –

-2

您的查詢應該是這樣的：

$query_matches = "SELECT cm_matches.match_id, cm_competitions.name FROM cm_matches INNER JOIN cm_competitions ON cm_matches.competition_id = cm_competitions.competition_id WHERE cm_matches.club_h_id = 8 OR cm_matches.club_v_id = 8";

來源

2013-07-23 08:27:24 Konsole

也沒有解釋。問題已經回答 –

這個問題在我提交時沒有回答。而且我錯過了解釋。認爲這是自解釋:) – Konsole

這是基本的語法，因爲作者不知道它，它似乎沒有閱讀文檔。你可能會提到，FROM子句在JOIN之前，也許連接了官方文檔 –

Mysql查詢內部連接？

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