一個更好的/合適/健壯的答案很可能會創造一個MySQL程序這一點,但如果您的數據能夠適應這些限制,你可以用下面的:
- 不超過5級(或根據需要擴大的圖案)
- ID是不超過6個位數(或改變的concat表達式)
此查詢使用的毗連建立一個排序參考使得A的孩子來甲等後的名稱使用concat和前導空格手動縮進。
select concat(1000000 + a.id, '|') SORT
,a.name
from categories a
where a.parent = 1 # top level parents only
union all
select concat(1000000 + a.id, '|',
1000000 + IFNULL(b.id,0), '|')
,concat(' - ', b.name)
from categories a
inner join category_relationships a1 on a1.parent_id = a.id
inner join categories b on b.id = a1.category_id
where a.parent = 1
union all
select concat(1000000 + a.id, '|',
1000000 + IFNULL(b.id,0), '|',
1000000 + IFNULL(c.id,0), '|')
,concat(' - ', c.name)
from categories a
inner join category_relationships a1 on a1.parent_id = a.id
inner join categories b on b.id = a1.category_id
inner join category_relationships b1 on b1.parent_id = b.id
inner join categories c on c.id = b1.category_id
where a.parent = 1
union all
select concat(1000000 + a.id, '|',
1000000 + IFNULL(b.id,0), '|',
1000000 + IFNULL(c.id,0), '|',
1000000 + IFNULL(d.id,0), '|')
,concat(' - ', d.name)
from categories a
inner join category_relationships a1 on a1.parent_id = a.id
inner join categories b on b.id = a1.category_id
inner join category_relationships b1 on b1.parent_id = b.id
inner join categories c on c.id = b1.category_id
inner join category_relationships c1 on c1.parent_id = c.id
inner join categories d on d.id = c1.category_id
where a.parent = 1
union all
select concat(1000000 + a.id, '|',
1000000 + IFNULL(b.id,0), '|',
1000000 + IFNULL(c.id,0), '|',
1000000 + IFNULL(d.id,0), '|',
1000000 + IFNULL(e.id,0))
,concat(' - ', e.name)
from categories a
inner join category_relationships a1 on a1.parent_id = a.id
inner join categories b on b.id = a1.category_id
inner join category_relationships b1 on b1.parent_id = b.id
inner join categories c on c.id = b1.category_id
inner join category_relationships c1 on c1.parent_id = c.id
inner join categories d on d.id = c1.category_id
inner join category_relationships d1 on d1.parent_id = d.id
inner join categories e on e.id = d1.category_id
order by SORT
分層查詢 - 哎喲...會很難。除非您事先知道層次結構的最大深度,否則除非DBMS支持「WITH RECURSIVE」子句(或非標準擴展,如「CONNECT BY」),否則無法編寫通用解決方案。 – 2011-01-23 22:26:34